[英]Java Regex matching between curly braces
I need to parse a log file and get the times and associated function call string This is stored in the log file as so: {"time" : "2012-09-24T03:08:50", "message" : "Call() started"}我需要解析一个日志文件并获取时间和相关的函数调用字符串 这在日志文件中存储如下: {"time" : "2012-09-24T03:08:50", "message" : "Call( ) 开始"}
There will be multiple logged time function calls in between other string characters, so hence I am hoping to use regex to go through the file and grab all of these在其他字符串字符之间会有多个记录的时间函数调用,因此我希望使用正则表达式来浏览文件并获取所有这些
I would like to grab the entire logged information including the curly brackets我想获取包括大括号在内的整个记录信息
I have tried the following我已经尝试了以下
Pattern logEntry = Pattern.compile("{(.*?)}");
Matcher matchPattern = logEntry.matcher(file);
and和
Pattern.compile("{[^{}]*}");
Matcher matchPattern = logEntry.matcher(file);
I keep getting illegal repetition errors, please help!我不断收到非法重复错误,请帮助! Thanks.
谢谢。
you need to escape '{' & '}' with a '\\'你需要用 '\\' 转义 '{' & '}'
so: "{(.*?)}"
becomes: "\\\\{(.*?)\\\\}"
所以:
"{(.*?)}"
变成: "\\\\{(.*?)\\\\}"
where you have to escape the '\\' with another '\\' first你必须先用另一个 '\\' 转义 '\\'
see: http://www.regular-expressions.info/reference.html for a comprehensive list of characters that need escaping...请参阅: http : //www.regular-expressions.info/reference.html以获取需要转义的字符的完整列表...
Braces
are special regex characters used for repetition groups, therefore you must escape them. Braces
是用于重复组的特殊正则表达式字符,因此您必须对它们进行转义。
Pattern logEntry = Pattern.compile("\\{(.*?)\\}");
Simple tester:简单的测试器:
public static void main(String[] args) throws Exception {
String x = "{\"time\" : \"2012-09-24T03:08:50\", \"message\" : \"Call() started\"}";
Pattern logEntry = Pattern.compile("\\{(.*?)\\}");
Matcher matchPattern = logEntry.matcher(x);
while(matchPattern.find()) {
System.out.println(matchPattern.group(1));
}
}
Gives me:给我:
"time" : "2012-09-24T03:08:50", "message" : "Call() started"
You should use a positive lookahead and lookbehind:您应该使用积极的前瞻和后视:
(?<=\{)([^\}]+)(?=\})
{} in regexp have special meaning, so they need to be escaped. regexp 中的 {} 有特殊含义,需要转义。
Usually escaping is achieved by preceeding the character to be escaped with a backslash.通常转义是通过在要转义的字符前面加上反斜杠来实现的。 In a character class defined with square brackets, you shouldn't need to do this
在用方括号定义的字符类中,您不需要这样做
So something like所以像
Pattern.compile("\{[^{}]*\}");
Could be nearer to what you want to do可能更接近你想做的事
This works perfectly for non-nested brackets but for expressions like这对于非嵌套括号非常适用,但对于像这样的表达式
(sum(x) * 100) / (sum(y) + sum(z))
[az]*[\\{]+([a-zA-Z0-9]+)[\\}]+
works. [az]*[\\{]+([a-zA-Z0-9]+)[\\}]+
有效。
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