如何在java中转换wav文件

Question

How can I convert a wav file in java

AudioFormat targetFormat = new AudioFormat(
                                    sourceFormat.getEncoding(),
                                    fTargetFrameRate,
                                    16,
                                    sourceFormat.getChannels(),
                                    sourceFormat.getFrameSize(),
                                    fTargetFrameRate,
                                    false);

in result Exception :

java.lang.IllegalArgumentException: Unsupported conversion: 
ULAW 8000.0 Hz, **16 bit**, mono, 1 bytes/frame, **from** ULAW 8000.0 Hz, **8 bit**, mono, 1 bytes/frame

it is possible in java?

I need get wav file 16 bit, from 8

Answer 1

Here is a method that will convert an 8-bit uLaw encoded binary file into a 16-bit WAV file using built-in Java methods.

public static void convertULawFileToWav(String filename) {
    File file = new File(filename);
    if (!file.exists())
        return;
    try {
        long fileSize = file.length();
        int frameSize = 160;
        long numFrames = fileSize / frameSize;
        AudioFormat audioFormat = new AudioFormat(Encoding.ULAW, 8000, 8, 1, frameSize, 50, true);
        AudioInputStream audioInputStream = new AudioInputStream(new FileInputStream(file), audioFormat, numFrames);
        AudioSystem.write(audioInputStream, Type.WAVE, new File("C:\\file.wav"));
    } catch (IOException e) {
        e.printStackTrace();
    }
}

Answer 2

看看这一个： 转换音频格式它类似于你的问题建议查看http://docs.oracle.com/javase/6/docs/api/javax/sound/sampled/AudioSystem.html

Answer 3

You can always use FFMPEG, http://ffmpeg.org/ , to do the conversion. Your Java program can call FFMPEG to do the conversion.
FFMPEG works on all OS.