解析字符串以删除空格java

Question

I need some help parsing a string that is input to one that is later cleaned and output.

eg

String str = " tHis  strIng is  rEalLy mEssy  "

and what I need to do is have it parsed from that to look like this:

"ThisStringIsReallyMessy"

so I basically need to clean it up then set only the first letter of every word to capitals, without having it break in case someone uses numbers.

Answer 1

Apache Commons to the rescue (again). As always, it's worth checking out the Commons libraries not just for this particular issue, but for a lot of functionality.

You can use Apache Commons WordUtils.capitalize() to capitalise each word within the string. Then a replaceAll(" ", "") will bin your whitespace.

String result = WordUtils.capitalize(str).replaceAll(" ", "");

Note (other) Brian's comments below re. the choices behind replace() vs replaceAll() .

Answer 2

   String str = " tHis  strIng is  rEalLy mEssy  ";
   str =str.replace(" ", "");
   System.out.println(str);

output:

tHisstrIngisrEalLymEssy

For capitalizing first letter in each word there is no in-built function available, this thread has possible solutions.

Answer 3

String[] tokens = " tHis  strIng is  rEalLy mEssy  ".split(" ");
StringBuilder result = new StringBuilder();
for(String token : tokens) {
    if(!token.isEmpty()) {
        result.append(token.substring(0, 1).toUpperCase()).append(token.substring(1).toLowerCase());
     }
}
System.out.println(result.toString()); // ThisStringIsReallyMessy

Answer 4

你是说这个吗？

str = str.replaceAll(" ", "");