将行从一个表移动到另一个表（插入值列表与列列表不匹配）

Question

I am using Laravel PHP framework's Fluent query builder to move rows from one table to another. PDO is being used. While using the raw query DB::query() , I get the error:

Error

SQLSTATE[21S01]: Insert value list does not match column list: 
1136 Column count doesn't match value count at row 1

SQL: INSERT IGNORE into listings_archive VALUES (?, ?)

Query

// Get rows from first table
$rows = DB::table('table_1')
        ->where('id', '>', '12345')
        ->get();

// Copy rows to second table
foreach($rows as $row) {
    $listing = get_object_vars($row);
    DB::query('INSERT IGNORE into table_2 VALUES (?, ?)', $row);
}

var_dump of $row

array(39) {
    ["id"]=>
    string(7) "2511877"
    ["name"]=>
    string(2) "AB"
    ["color"]=>
    NULL
    ["type"]=>
    NULL
    ...

What is causing the error and how can it be fixed? I tried removing the elements with NULL s but still get the same error!

---

UPDATE

This is possibly a problem with the array being passed into DB::query() . These very simple example gave similar errors:

$row = array('id', 123);
DB::query('INSERT IGNORE into table_2 VALUES (?, ?)', $row);

and

$row = array('id' => 123);
DB::query('INSERT IGNORE into table_2 VALUES (?, ?)', $row);

Error

SQLSTATE[21S01]: Insert value list does not match column list: 
1136 Column count doesn't match value count at row 1

Answer 1

Well the column count doesn't match the number of values. If you don't specify which columns, it defaults to all, so you want something like

Insert IGNORE into table_2(Column1,Column2) Values (?, ?)

Column1, Column2, being the names of the two columns in table_2 you want to put the values from Table_1 into.

Answer 2

Had the same Error msg, but i used mysqli in php

• basically as stated above, if tables not identical in structure, you gotta name the fields

Solved by some tinkering:

$stmt = $con->prepare("INSERT INTO table2
                              (field1, field2, ..., )
                              SELECT
                              field1, field2, ..., 
                              FROM
                              table1 WHERE field = ? ");