[英]START TRANSACTION within a stored procedure within a START TRANSACTION mysql
From the mysql docs, it appears ambiguous as to whether calling 从mysql文档来看,关于是否调用
START TRANSACTION;
...
COMMIT;
from within a subroutine will automatically commit the "progress" of the outer caller's TRANSACTION, or whether it will simply add a reference to the outer caller's TRANSACTION, and wait until the final COMMIT in the outer caller (based on this ref-counting scheme) before the changes actually appear in the data tables. 子例程中的内容将自动提交外部调用者的TRANSACTION的“进度”,或者是否将简单地添加对外部调用者的TRANSACTION的引用,并等待直到外部调用者中的最终COMMIT(基于此引用计数方案)在更改实际出现在数据表之前。
Which is correct? 哪个是对的? Perhaps I'm confused from Googling too much, and just hoping for the nested scenario to be reality... 也许我对谷歌搜索太多感到困惑,只是希望嵌套的场景成为现实...
Additional question: If the nested/ref-counted prescription is not "correct", why was it designed this way? 附加问题:如果嵌套/引用计数处方不是“正确”的,为什么要这样设计? Thanks. 谢谢。
SET AUTOCOMMIT=0
then 然后
START TRANSACTION;
...
COMMIT;
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