[英]How to input data into table from MySQL?
I've created a page that is supposed to pull all the domains from my database and display them in a table. 我创建了一个页面,该页面应该从数据库中提取所有域并将其显示在表中。 Pagination is setup to show 1002 domains per page and the table should be 3 columns. 分页设置为每页显示1002个域,该表应为3列。
When I'm not sure what to do is towards the end where you can see "Row Test1" and "Row Test1" - those show up on the page correctly. 当我不确定要做什么时,可以在最后看到“行测试1”和“行测试1”-这些正确显示在页面上。 However, how do I make it so that instead of showing those, it will actually show the domains from my database. 但是,我如何做到这一点,而不是显示它们,而是实际显示数据库中的域。
If someone can post an example of the fixed part of the code it would be highly appreciated, I feel like I've been trying so many things and it's getting a bit confusing. 如果有人可以发布示例代码的固定部分,将不胜感激,我觉得我已经尝试了很多事情,并且变得有些混乱。
Here's the entire code: 这是完整的代码:
<?php include("header.html"); ?>
<center>
<?php
/*
Place code to connect to your DB here.
*/
include('database.php'); // include your code to connect to DB.
$tbl_name="list"; //your table name
// How many adjacent pages should be shown on each side?
$adjacents = 3;
/*
First get total number of rows in data table.
If you have a WHERE clause in your query, make sure you mirror it here.
*/
$query = "SELECT COUNT(*) as num FROM $tbl_name";
$total_pages = mysql_fetch_array(mysql_query($query));
$total_pages = $total_pages[num];
/* Setup vars for query. */
$targetpage = "index.php"; //your file name (the name of this file)
$limit = 1002; //how many items to show per page
$page = $_GET['page'];
if($page)
$start = ($page - 1) * $limit; //first item to display on this page
else
$start = 0; //if no page var is given, set start to 0
/* Get data. */
$sql = "SELECT website FROM $tbl_name LIMIT $start, $limit";
$result = mysql_query($sql);
/* Setup page vars for display. */
if ($page == 0) $page = 1; //if no page var is given, default to 1.
$prev = $page - 1; //previous page is page - 1
$next = $page + 1; //next page is page + 1
$lastpage = ceil($total_pages/$limit); //lastpage is = total pages / items per page, rounded up.
$lpm1 = $lastpage - 1; //last page minus 1
/*
Now we apply our rules and draw the pagination object.
We're actually saving the code to a variable in case we want to draw it more than once.
*/
$pagination = "";
if($lastpage > 1)
{
$pagination .= "<div class=\"pagination2\">";
//previous button
if ($page > 1)
$pagination.= "<a href=\"$targetpage?page=$prev\">< previous</a>";
else
$pagination.= "<span class=\"disabled\">< previous</span>";
//pages
if ($lastpage < 7 + ($adjacents * 2)) //not enough pages to bother breaking it up
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
}
elseif($lastpage > 5 + ($adjacents * 2)) //enough pages to hide some
{
//close to beginning; only hide later pages
if($page < 1 + ($adjacents * 2))
{
for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a href=\"$targetpage?page=$lpm1\">$lpm1</a>";
$pagination.= "<a href=\"$targetpage?page=$lastpage\">$lastpage</a>";
}
//in middle; hide some front and some back
elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
{
$pagination.= "<a href=\"$targetpage?page=1\">1</a>";
$pagination.= "<a href=\"$targetpage?page=2\">2</a>";
$pagination.= "...";
for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a href=\"$targetpage?page=$lpm1\">$lpm1</a>";
$pagination.= "<a href=\"$targetpage?page=$lastpage\">$lastpage</a>";
}
//close to end; only hide early pages
else
{
$pagination.= "<a href=\"$targetpage?page=1\">1</a>";
$pagination.= "<a href=\"$targetpage?page=2\">2</a>";
$pagination.= "...";
for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
}
}
//next button
if ($page < $counter - 1)
$pagination.= "<a href=\"$targetpage?page=$next\">next ></a>";
else
$pagination.= "<span class=\"disabled\">next ></span>";
$pagination.= "</div>\n";
}
?>
<?php
$i = 0;
echo '<table><tr>';
while($row = mysql_fetch_array($result))
{
$i ++;
if ($i<=2)
{
echo '<td>
<div>Row Test1</div>
</td>';
}
else
{
echo '</tr><tr>';
echo '<td><div>Row Test2</div></td>';
$i = 0;
}
}
echo '</tr></table>';
?>
<?=$pagination?>
</center>
<?php include("footer.html"); ?>
I am a bit unsure why you need to split your row prints in your while statement. 我有点不确定为什么需要在while语句中拆分行打印。 The while statement will print out results for all that whether that be one, twenty, or none so long as the statement evaluates true.. while语句将打印所有结果,无论该结果是1、20还是不显示,只要该语句的值为true。
<?php
$i = 0;
echo '<table><tr>';
while($row = mysql_fetch_array($result)) {
$i ++;
echo '<td><div>'.$row[databasecolumnnamethatcontainsurlgoeshere].'</div></td>';
}
echo '</tr></table>';
?>
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