[英]sorting nsarray in ascending order
I have an NSdictonary object with following key values 我有一个NSdictonary对象具有以下键值
keys: 1.infoKey, 2.infoKey, 3.infoKey, 4.infoKey, 5.infoKey, 6.infoKey, 7.infoKey, 8.infoKey, 9.infoKey, 10.infoKey, 11.infoKey keys:1.infoKey,2.infoKey,3.infoKey,4.infoKey,5.infoKey,6.infoKey,7.infoKey,8.infoKey,9.infoKey,10.infoKey,11.infoKey
Note they are not sorted and can be in any order ie 3.infoKey, 7.infoKey, 2.infoKey etc 注意它们没有排序,可以是任何顺序,即3.infoKey,7.infoKey,2.infoKey等
What I am trying to do is sort the key values out ie 1,2,3,4,5,6,7,8,9,10,11 .... This is the code I have used so far but every time I do a sort, it sorts it in order that I don't want (see below) 我想要做的是排除键值,即1,2,3,4,5,6,7,8,9,10,11 ....这是我到目前为止使用的代码,但每次我做了一个排序,它按照我不想要的方式对其进行排序(见下文)
NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
NSString *stringsPlistPath = [[paths objectAtIndex:0] stringByAppendingPathComponent:@"talkBtns.plist"];
NSMutableDictionary *dictionary2 = [[NSMutableDictionary alloc] initWithContentsOfFile:stringsPlistPath];
NSArray *myKeys = [dictionary2 allKeys];
//This didn't give the right results
//sortedKeys = [myKeys sortedArrayUsingSelector:@selector(caseInsensitiveCompare:)];
//This didn't give the right results either
NSSortDescriptor* sortDescriptor = [NSSortDescriptor sortDescriptorWithKey:nil ascending:YES selector:@selector(localizedCompare:)];
sortedKeys = [myKeys sortedArrayUsingDescriptors:[NSArray arrayWithObject:sortDescriptor]];
// ***********
// GET KEY VALUES TO
// LOOP OVER
// ***********
/* */
for (int i = 0; i < [sortedKeys count]; i++)
{
NSLog(@"[sortedKeys objectAtIndex:i]: %@", [sortedKeys objectAtIndex:i]);
}
//output I get
[sortedKeys objectAtIndex:i]: 1.infoKey
[sortedKeys objectAtIndex:i]: 10.infoKey
[sortedKeys objectAtIndex:i]: 11.infoKey
[sortedKeys objectAtIndex:i]: 2.infoKey
[sortedKeys objectAtIndex:i]: 3.infoKey
[sortedKeys objectAtIndex:i]: 4.infoKey
[sortedKeys objectAtIndex:i]: 5.infoKey
[sortedKeys objectAtIndex:i]: 6.infoKey
[sortedKeys objectAtIndex:i]: 7.infoKey
[sortedKeys objectAtIndex:i]: 8.infoKey
[sortedKeys objectAtIndex:i]: 9.infoKey
I tried both ways and they both give the same results. 我尝试了两种方式,他们都给出了相同的结果。 I searched every where on stack overflow and google but couldn't find a fit for my needs. 我搜索堆栈溢出和谷歌的每个地方,但找不到适合我的需求。
Any suggestions? 有什么建议么?
You should be able to sort it using sortedArrayUsingComparator
with options:NSNumericSearch
to get it in real numeric order, since 10 comes before 2 in a strictly alphabetical sort; 您应该能够使用sortedArrayUsingComparator
进行排序options:NSNumericSearch
以实际数字顺序对其进行排序,因为10在严格按字母顺序排序之前出现在2之前;
NSArray * sortedKeys =
[myKeys sortedArrayUsingComparator:^(id string1, id string2) {
return [((NSString *)string1) compare:((NSString *)string2)
options:NSNumericSearch];
}];
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.