为什么swap（＆a ++，＆b ++）给出错误“一元'＆'中的无效左值”？

Question

#include<stdio.h>
int swap(int *a,int *b);
int main()
{
    int a=10,b=20;
    swap(&a++,&b++);
    printf("a=%d\nb=%d",a,b);
    return 0;
}

int swap(int *a,int *b)
{
    int temp;
    temp=*a;
    *a=*b;
    *b=temp;
}

Why does this function give the error "invalid lvalue in unary '&'"? Normal swap(&a,&b) works fine but swap(&a++,&b++) as well as swap(&(a++),&(b++)) give errors. What's the reason behind this?

Answer 1

The post-increment operator returns a temporary version of the previous value contained in the variable on which the post-increment operation was performed. This temporary value is not a l-value, or "named" memory location, therefore you can't take the address of that temporary using the unary address-of operator.

For instance, on certain architectures like x86, etc., a temporary value generated from the post-increment operator on a simple POD-type like a int , long etc. will be temporarily held in a CPU register, not an actual memory location. In these instances you simply can't take the "address" of a CPU register.