[英]php regex replace from array and square brackets
I want to find and replace only words which are in array keys. 我只想查找和替换数组键中的单词。 I try to do this with regex but only with partial succes.
我尝试使用正则表达式执行此操作,但只能使用部分成功。
For example: 例如:
$str = '[something][userName][userEmail][something]';
$user = array(
'id' => (string) '2',
'userName' => (string) 'super user',
'userEmail' => (string) 'superuser@some.domain',
);
// get the keys.
$keys = array_keys($user);
// get the values.
$values = array_values($user);
// surround each key in word boundary and regex delimiter
// also escape any regex metachar in the key
foreach($keys as &$key) {
$key = '/\b'.preg_quote($key).'\b/';
}
// do the replacement using preg_replace
echo preg_replace($keys,$values,$str);
This code produces: 此代码产生:
[something][super user][superuser@some.domain][something] [某物] [超级用户] [superuser@some.domain] [某物]
What I want to do to get rid the square brackets surrounding the 'super user' and 'superuser@some.domain' but not those surrounding [something] (at the start and finish of the string) 我想做些什么来消除围绕“超级用户”和“ superuser@some.domain”的方括号,而不是围绕[something]的方括号(在字符串的开头和结尾)
Please help. 请帮忙。 Regards
问候
why dont you just add square brackets to replace pattern? 您为什么不添加方括号来替换模式?
$str = '[something][userName][userEmail][something]';
/* ... */
foreach($keys as &$key) {
$keyWithSquareBrackets = '[' . $key . ']';
$key = '/\b'.preg_quote($keyWithSquareBrackets).'\b/';
}
// do the replacement using preg_replace
echo preg_replace($keys,$values,$str);
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