[英]How can I determine the elements in an array that do not exist in another array?
In Ruby I can do this: 在Ruby中,我可以这样做:
fruit = ['banana','apple','tangerine','orange','lemon','lime','kiwi','mango','guava']
citrus = ['orange','lemon','lime','tangerine']
others = fruit - citrus
And others
will contain an array of non-citrus fruits. others
将包含一系列非柑橘类水果。
How can I do this in PHP? 如何在PHP中做到这一点?
$fruit = array('banana','apple','tangerine','orange','lemon','lime','kiwi','mango','guava');
$citrus = array('orange','lemon','lime','tangerine');
$others = # NOW WHAT ?????
Do I need to iterate over each item in $citrus
and find its offset in $fruit
(if it exists in that array) and then unset it, and then use array_values() to fix the array's indices? 我是否需要遍历$citrus
每个项目,并在$fruit
找到其偏移量(如果它存在于该数组中),然后对其进行设置,然后使用array_values()来修复该数组的索引? Or is there a simpler, less error-prone way? 还是有一种更简单,更不易出错的方式?
Please note: I'm not looking for the intersection of the arrays. 请注意:我不是在寻找数组的交集 。 I'm looking for a complement . 我正在寻找一个补充 。 This was originally closed as a duplicate of a question asking the former. 最初是作为询问前一个问题的副本而关闭的。
Yes, there is array_diff()
which does exactly that: 是的,有array_diff()
可以做到这一点:
$others = array_diff($fruit, $citrus);
That'll leave you with: 这将使您拥有:
Array
(
[0] => banana
[1] => apple
[6] => kiwi
[7] => mango
[8] => guava
)
Which seems to be the expected remainder after subtracting citrus fruits from other fruits. 从其他水果中减去柑橘类水果后,这似乎是预期的剩余量。
You can just use array_diff
您可以只使用array_diff
$fruit = array('banana','apple','tangerine','orange','lemon','lime','kiwi','mango','guava');
$citrus = array('orange','lemon','lime','tangerine');
$others = array_diff($fruit, $citrus);
var_dump($others);
Output 输出量
array
0 => string 'banana' (length=6)
1 => string 'apple' (length=5)
6 => string 'kiwi' (length=4)
7 => string 'mango' (length=5)
8 => string 'guava' (length=5)
you can use array_diff()
: 您可以使用array_diff()
:
$others = array_merge(array_diff($fruit, $citrus));
You would need to use array_merge to arrange the indices. 您将需要使用array_merge来安排索引。 See it in action here 在这里看到它的作用
$others
will contain these values: $others
将包含以下值:
Array
(
[0] => banana
[1] => apple
[6] => kiwi
[7] => mango
[8] => guava
)
this can be done by array_intersect and array_diff 这可以通过array_intersect和array_diff来完成
$filter1 = "red,green,blue,yellow";
$parts1 = explode(',', $filter1);
$filter2 = "red,green,blue";
$parts2 = explode(',', $filter2);
$result = array_intersect($parts1 , $parts2 );
print_r($result);
and 和
$result = array_diff($parts1 , $parts2 );
print_r($result);
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