MySQL ORDER BY用户在另一个表中的总行

Question

Suppose, I want to show a list of users ordering by the most number of messages they have sent. 假设我想显示一个按用户发送的邮件数量排序的用户列表。

I have 2 tables: Users and Messages 我有2个表格： Users和Messages

I have 10 users 我有10位使用者

User A sent 20 messages (have 20 rows in Messages table) 用户A发送了20条消息（“消息”表中有20行）

SELECT * FROM messages WHERE user='A'


User B sent 17 msgs    
User C sent 19    
User D sent 13

and so on. 等等。

I want to a query that will list Users in order of their total messages sent. 我想要一个查询，该查询将按发送的邮件总数列出用户。 Like: 喜欢：

1. A (20 msgs)
2. C (19 msgs)
3. B (17 msgs)
4. D (13 msgs)

I tried hard but I can't find any query to execute this. 我尽力了，但找不到任何查询来执行此操作。 Please help. 请帮忙。 Thanks in advance. 提前致谢。

Answer 1

SELECT user, COUNT(*) FROM messages GROUP BY user ORDER BY count(*) DESC;

Answer 2

如果要打印名称加入用户表，

select user_name, count(*) from users inner join messages m on users.userid=m.messageid group by userid order by count(*) desc;

Answer 3

You can sort using an alias : 您可以使用alias进行排序：

SELECT user, COUNT(1) as cnt
FROM Messages 
GROUP BY user 
ORDER BY cnt DESC;

or position : 或position ：

SELECT user, COUNT(1) as cnt
FROM Messages 
GROUP BY user 
ORDER BY 2 DESC;