在一个循环python中崩溃

Question

How to solve this error? i want to pass the values from get_robotxya() and get_ballxya() and use it in a loop but it seems that it will crash after awhile how do i fix this? i want to get the values whithout it crashing out of the while loop

import socket
import os,sys
import time
from threading import Thread

HOST = '59.191.193.59'
PORT = 5555

COORDINATES = []

def connect():   
    globals()['client_socket'] = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    client_socket.connect((HOST,PORT))

def update_coordinates():
    connect()
    screen_width = 0
    screen_height = 0
    while True:
        try:
            client_socket.send("loc\n")
            data = client_socket.recv(8192)
        except:
            connect();
            continue;

        globals()['COORDINATES'] = data.split()

        if(not(COORDINATES[-1] == "eom" and COORDINATES[0] == "start")):
            continue

        if (screen_width != int(COORDINATES[2])):
            screen_width = int(COORDINATES[2])
            screen_height = int(COORDINATES[3])
            return

def get_ballxy():
    update_coordinates()
    ballx = int(COORDINATES[8])
    bally = int(COORDINATES[9])

    return ballx,bally

def get_robotxya():
    update_coordinates()
    robotx = int(COORDINATES[12])
    roboty = int(COORDINATES[13])
    angle = int(COORDINATES[14])
    return robotx,roboty,angle

def print_ballxy(bx,by):

    print bx
    print by

def print_robotxya(rx,ry,a):

    print rx
    print ry
    print a

def activate():

    bx,by = get_ballxy()
    rx,ry,a = get_robotxya()
    print_ballxy(bx,by)
    print_robotxya(rx,ry,a)


Thread(target=update_coordinates).start()
while True:
    activate()

this is the error i get:

Answer 1

I think you'll find that, because you're continuously creating new connections without closing them down, you'll eventually run out of resources.

That may be a local limitation or it may be the server end getting fed up with too many connections from a single IP.

Regardless, either create one connection and use it over and over, or shut down connections when you're done with them.

---

One possible way of doing this is to connect() within the main code before calling activate() :

connect()
update_coordinates()
while True:
    activate()

Then remove the initial connect() from the start of the update_coordinates() function since that's the bit that does a new connection every time you try to update the coordinates.

If the session goes down for some reason, the except bit will re-create it and try again.

That should hopefully alleviate your resource problem quite a bit.