[英]How to write this query with the following schema?
I have the database schema as follows: 我的数据库架构如下:
Teams(teamID,teamName,home,leagueName)
Games(gameID,homeTeamID,guestTeamID,date)
How can I query(using SQL) all teamID
s where the team played against the team1 but not against the team2. 如何查询(使用SQL)团队对着team1而不对着teamID
的所有teamID
。 'team1 and team2 are some data values in the column teamName
? 'team1和team2是teamName
列中的一些数据值?
Assuming that there is no game without HomeTeam
or GuestTeam
. 假设没有HomeTeam
或GuestTeam
没有游戏。 Try this one, 试试这个
SELECT a.gameID,
b.TeamName AS HomeTeam,
c.TeamName AS GuestTeam,
a.`date`
FROM GAMES a
INNER JOIN Teams b
ON a.homeTeamID = b.teamID
INNER JOIN Teams c
ON a.guestTeamID = c.teamID
WHERE (
b.TeamName = 'Team1' AND
c.teamName <> 'Team2'
)
OR
(
c.TeamName = 'Team1' AND
b.teamName <> 'Team2'
)
All teamIDs where the team played against the team1 but not against the team2 团队与team1对抗而不与team2对抗的所有teamID
SELECT t1.teamName AS 'Home', t2.TeamName AS 'Guest', g.Date
FROM
(
SELECT *
FROM Games
WHERE (homeTeamID = 'Team 1' OR guestTeamID = 'Team 1')
AND (homeTeamID <> 'Team 2' OR guestTeamID <> 'Team 1')
) g ON t.teamID = hg.homeTeamID
INNER JOIN teams t1 ON g.homeTeamID = t1.teamId
INNER JOIN teams t2 ON g.guestTeamID = t2.teamId
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