Qt接口类

Question

How can I create an interface class, something like this :

template<typename file_system_t>
    class ireciver_intervace : public QObject
    {
        public:
        typedef typename file_system_t::file_system_item file_system_item;
    public Q_SLOTS:
        virtual void dataChangeItem(file_system_item *item)=0;
        virtual void removeItem(file_system_item *item)=0;
        virtual void insertItem(file_system_item *item)=0;
    };

and derived class

class FileItemModel:public QAbstractItemModel ,public ireciver_intervace<file_system>
        {
            Q_OBJECT
        }

When I inherit from this class I get an error mentioning ambiguous conversions. I understand this is the right behavior of the compiler, but how can I get interfaces slots for my future classes? Maybe I must use the Q_DECLARE_INTERFACE macro?

Answer 1

QObject subclasses with signal/slot functionality can't be templated.

You can simply drop the QObject inheritance of your interface, the rest will be fine. It's no problem to define a (pure) virtual function and then (in the subclass) make a slot out of it by putting it in the slots section of your subclass:

template<typename file_system_t>
class ireceiver_interface
{
public:
    typedef typename file_system_t::file_system_item file_system_item;

    // pure virtual functions (NO SLOTS!):
    virtual void dataChangeItem(file_system_item *item)=0;
    virtual void removeItem(file_system_item *item)=0;
    virtual void insertItem(file_system_item *item)=0;
};

class FileItemModel: public QAbstractItemModel,
                     public ireceiver_interface<file_system_t>
{
    Q_OBJECT
    ...
public slots:
    // implementations (slots):
    virtual void dataChangeItem(file_system_item *item);
    virtual void removeItem(file_system_item *item);
    virtual void insertItem(file_system_item *item);
    ...
}

However, the idea of an interface is to define what functions a concrete class has to implement. Here, the interface can't force the subclass to define those functions as slots , it can also define them as non-slot functions . This minor problem can't be solved. Even if the interface could be a QObject, the subclass could then decide to re-implement those methods as non-slots!

_{Note that you have two typos in your class name: It's receiver , not reciver and it's interface , not intervace .}

Answer 2

You can't inherit from more than one QObject . However, both classes you inherit from are QObjects .

Some possibilities you could consider are the following:

• Let the class ireciver_intervace inherit from QAbstractItemModel instead of QObject . This way, FileItemModel can simply inherit from ireciver_intervace . (may not be possible depending on what you want to achieve)
• Use delegation for the QAbstractItemModel instead of inheritance.