[英]PHP pass variable to the function's return
Is it possible to do something like this: 是否可以做这样的事情:
Class::function('some_text') = 'aaaaa';
And get this 'aaaaa' string inside the Class::function() ? 并在Class :: function()中获取此“ aaaaa”字符串?
Yes it is by doing this: 是的,它是通过执行以下操作:
MyClass::func('some_text', 'aaaaa');
Eg 例如
class MyClass {
public static function func($text, $aaa) {
...
}
}
Alternatively (and much worse then the previous IMHO): 或者(比以前的恕我直言更糟):
global $foo;
$foo = 'bar';
class Baz {
public static function bong() {
global $foo;
...
}
}
That syntax is not available in PHP. 该语法在PHP中不可用。
In Perl, this type of function would be called an LVALUE function
. 在Perl中,这种类型的函数称为
LVALUE function
。
With your case it seems like you're searching for a solution like this? 对于您的情况,似乎您正在寻找这样的解决方案?
Session::Set(array("key" => "value"));
class Session {
public static function Set($kvp) {
foreach ($kvp as $key => $value) {
echo $key . " is " . $value . "<br />";
}
}
}
you can return a reference and change the value of it. 您可以返回参考并更改其值。
class MyClass {
private static $variable;
public static function &func($random_param) {
return self::$variable;
}
}
call it like this 这样称呼它
$reference = &MyClass::func('asd');
$reference = "15";
echo MyClass::func('asdasd'); // "15"
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