正则表达式，排除某些单词以外的所有单词

Question

I though that filtering a string like : "Hello <strong>plip</strong> plop" to obtain "plip plop" , that is, excluding all words except 'plip' and 'plop' would be easy with this C# line: new Regex("[^(plip)(plop)]").Replace(inputString,"") . Unfortunalty, the excluding brackets [^] seem to not accept exclusion words, as it keeps each letters contained in 'plip' and 'plop' (the result is "llooplipoplop" ).

Is there a way to achieve this in a single regex/line, or is it necessary to loop other all matches of plip and plop, then concat them?

Answer 1

hope this works

(?<=(\bplip\b|\bplop\b|^)).*?(?=(\bplip\b|\bplop\b|$))

You should set the singleline mode for the above regex to work

works here

Answer 2

Generally speaking, it is much easier to write a regex that matches what you do want than one that matches all the stuff you don't want.

In this case you want to "exclude all words except plip and plop ", but why not just include only plip and plop instead?

var input = "Hello <strong>plip</strong> plop";
var matches = Regex.Matches(input, "plip|plop");
var result = string.Join("", matches.Cast<Match>().Select(x => x.Value));

Console.Out.WriteLine(result); // prints "plipplop"

Of course since you asked for a one-liner, you could do everything without the temp variables (and good luck to the next guy reading the code!):

var result = string.Join("", Regex.Matches("Hello <strong>plip</strong> plop", "plip|plop").Cast<Match>().Select(x => x.Value));

Also, assuming you actual word list is more complicated than plip and plop , you can do something like var pattern = string.Join("|", words); to construct the pattern.