使用NSXMLParser的具有属性的iOS XML

Question

I want to parse an XML file and want to show the information in an TableView.

At first my XML file:

<?xml version="1.0" encoding="UTF-8"?>
<machines>
<machine id="1" project="100" name="first" status="inactive" />
<machine id="115" project="101" name="second" status="alive" />
<machine id="252" project="456" name="etc" status="alive" />
</machines>

And here my starting Ocj-C code:

- (void)parser:(NSXMLParser *)parser didStartElement:...{

if([elementName isEqualToString:@"machine"]){
    machine =[[Machines alloc]init];
}
}

- (void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string
{
[nodecontent appendString:[string stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]]];
NSLog(@"node content = %@",nodecontent);
}

- (void)parser:(NSXMLParser *)parser didEndElement:...
{
if([elementName isEqualToString:@"machine"]){
    machine.name=nodecontent;
    [tableArray addObject:machine];
    [machine release];
    machine = nil;
}
}

1. The NSLog for the nodecontent has no output.

2. How can i save the attibutes of an element? (got a class "Machines", here are id, project, name and status)

Hope someone can help me :)

Answer 1

The - (void)parser:didStartElement:namespaceURI:qualifiedName:attributes: gives you this information in a dictionary (see the attributes argument). It is then up to you to save it off and do with it what you please.

For more information, see: Parsing XML data with NSXMLParser and NSXMLParser Class Reference