是否可以仅将“选项值”与数据库记录的第一个数字进行比较？

Question

Sorry for the fairly ambiguous and long question. 很抱歉，这个模棱两可且冗长的问题。

I am creating a search form for a packaging database and over the past few days I have had a few problems with creating one of the forms that searches for the height of a packet. 我正在为包装数据库创建搜索表单，并且在过去几天中，在创建其中一种用于搜索数据包高度的表单时遇到了一些问题。 I want the form to display all results associated with a users input instead of it just returning the exact results. 我希望表单显示与用户输入关联的所有结果，而不是仅仅返回确切的结果。 I couldn't get anything like that working. 我什么都做不到。 So I have resorted to creating a dropdown box that searches within a range. 因此，我不得不创建一个在一定范围内搜索的下拉框。

HTML Dropdown: HTML下拉列表：

        <body>
               <label for="trayheight">Height: </label>
                <select name="trayheight">
                    <option value="">All</option>
                    <option value="1">100 - 199 range</option>
                    <option value="2">200 - 299 range</option>
                    <option value="3">300 - 399 range</option>
                </select><br />
        </body>

Here is the dropdown ranges (I also will be adding a range that searches for the 70 - 80 packets). 这是下拉范围（我还将添加一个范围来搜索70-80个数据包）。 As you can see the option value in each just consists of one number ("1,2,3"), this is so the database will return any results that has (for example) a 1 in it. 如您所见，每个选项值仅由一个数字（“ 1,2,3”）组成，因此数据库将返回其中（例如）为1的任何结果。 So if a user searches for something in the "100-199" range, the SQL query will return all the results that are within that range, but currently also return anything with a "1" in it eg height "201". 因此，如果用户搜索“ 100-199”范围内的内容，SQL查询将返回该范围内的所有结果，但当前还会返回其中包含“ 1”的任何内容，例如高度“ 201”。 I want to change it so the SQL query will take the value and then use it to compare it to the first number in a record eg the 1 in (1)21, so the results that return should only be within that range and nothing else such as "212" won't return. 我想对其进行更改，以便SQL查询将获取该值，然后将其用于与记录中的第一个数字进行比较，例如（1）21中的1，因此返回的结果应仅在该范围内，而没有其他值如“ 212”将不会返回。 Is there some form of server code that would deal with this? 有某种形式的服务器代码可以处理此问题吗？

Here is my server side code: 这是我的服务器端代码：

       <body>

        <?php
            $con = mysql_connect ("localhost", "root", "");
                   mysql_select_db ("delyn_db", $con);

            if (!$con)
                { 
                    die ("Could not connect: " . mysql_error());
                }

            $descrip = mysql_real_escape_string($_POST['descrip']); 
            $width   = mysql_real_escape_string($_POST['width']);
            $depth   = mysql_real_escape_string($_POST['depth']);

            $varHeight= mysql_real_escape_string($_POST['trayheight']);
            $varRange = mysql_real_escape_string($_POST['trayrange']);
            $varType  = mysql_real_escape_string($_POST['traytype']);
            $varShape = mysql_real_escape_string($_POST['trayshape']);
            $varImage = mysql_real_escape_string($_POST['imagename']);

            $sql = "SELECT * FROM delyn WHERE 
                        description LIKE '%".$descrip."%'  
                    AND trayheight  LIKE '%".$varHeight."%'
                    AND trayrange   LIKE '%".$varRange."%' 
                    AND traytype    LIKE '%".$varType."%' 
                    AND trayshape   LIKE '%".$varShape."%'";


            $r_query = mysql_query($sql);

                while ($row = mysql_fetch_array($r_query))
                    { 
                        echo '<br /> <img src="   '. $row['imagename'] . '" width="180" length="100">';
                        echo '<br /> Tool Code:   '. $row['toolcode'];
                        echo '<br /> Description: '. $row['description']; 
                        echo '<br /> Tray range:  '. $row['trayrange']; 
                        echo '<br /> Tray type:   '. $row['traytype'];
                        echo '<br /> Tray size:   '. $row['traysize']; 
                        echo '<br /> Tray shape:  '. $row['trayshape'] . '<br />' . '<br />';  
                    }

                if (mysql_num_rows($r_query) <= 0){
                    echo 'No results match your search, please try again';
               }


        ?>
      </body>

Thanks guys. 多谢你们。

Answer 1

Just construct the range: 只需构造范围：

if (isset($varHeight) && !empty($varHeight)) {
    $low = intval($varHeight."00");
    $high= intval($varHeight."99");
} else {
   $low = intval("000");
   $high= intval("999");
}

and change the sql query to search for this range: 并更改sql查询以搜索此范围：

AND trayheight  LIKE '%".$varHeight."%'

to 至

"AND trayheight  BETWEEN '".$low."' AND '".$high."'"

Of course proper validation should be placed to ensure that $varHeight is a number (presumably between 1 and 9) 当然，应该进行适当的验证以确保$varHeight是一个数字（大概在1到9之间）

UPDATED in order to catch the absence of $varHeight filter. 更新为了赶缺乏$varHeight过滤器。 This assumes that the total minimum of all possible values for $varHeight is 000 and the total maximum is 999 假定$varHeight的所有可能值的总最小值为000 ，而总最大值为999

是否可以仅将“选项值”与数据库记录的第一个数字进行比较？

问题描述

1 个解决方案

解决方案1
0 已采纳 2012-10-12 08:09:09

是否可以仅将“选项值”与数据库记录的第一个数字进行比较？

问题描述

1 个解决方案

解决方案1 0 已采纳 2012-10-12 08:09:09

解决方案1
0 已采纳 2012-10-12 08:09:09