在PHP表单之间传递变量。

Question

This is probably a really easy question but its early so yeah...

Basically I have a form:

<form name="varsForm" action="step2.php" id="formID" method="post">

And as I understand it within this for I created some hidden variables. as follows:

<input type="hidden" id="typeid" name="typeid" value="1" />

Because step2.php is set as an action, I though I was correct in assuming that the hidden variables would be passed to step2.php. However when I try to call them I am confronted with errors. I try and call them simply as follows:

<?php echo $_GET['typeid']; ?>

But it says that caseid is an undefined index, I assume I am not calling it correctly, anyone just put me right please?

Answer 1

You are submitting form via POST method, try $_POST['typeid'];

Alternatively change method to GET .

Answer 2

Since you are using method="post" in form, you should use

<?php echo $_POST['typeid']; ?>

$_GET in PHP is used when you use HTTP GET method (method="get" in form tag).

Answer 3

You're using the $_GET array while you're posting your infos.

You should use the $_POST array, or even the $_REQUEST array which handles both POST and GET.

Answer 4

You have method="post" so the data is placed in the message body and not the query string. It will be accessible via $_POST not $_GET .

Answer 5

You are using method="post" so look in $_POST :)

<?php echo $_POST['typeid']; ?>

HTH

Answer 6

Since you are using HTTP POST method in your <form> you need to give the code as:

<?php echo $_POST['typeid']; ?>

Else, in the HTML change this:

<form method="get">

Answer 7

You have method attribute in the form set to POST so values passed to step2.php will not be available in $_GET , it will be available in $_POST so to access the value you need to use $_POST['typeid'] .

And also Some times to avoid warnings OR notifications regarding index ( such as undefined index ) , you can first check for its existence and then process

Some what like this

if (array_key_exists('typeid', $_POST) )
{
     $typeid = $_POST['type_id'];
    // And do what ever you want to do with this value 
}