找到2个争论的最小值

Question

I cannot find the syntax error here. Can anyone please help me to find this ?

Question is this - (2) Write a program to get 2 values as command line arguments and find the Minimum of those 2 using if-else.

class MinNumber{

{
public static void main(String [] myArray){

    int length = myArray.length;

    if((myArray[0][0]) < (myArray[0][1])){
        System.out.println("Minimum number is : " + myArray[0][0]);
        }
    else{
        System.out.println("Minimum number is : " + myArray[0][1]);
        }
}

Answer 1

You can not compare String value with < since it is not primitive Also Array is single array not double array.

Below is not safe code but simplest :

    if (Integer.parseInt(myArray[0]) < Integer.parseInt(myArray[1])) {
        System.out.println("Minimum number is : " + myArray[0]);
    } else {
        System.out.println("Minimum number is : " + myArray[1]);
    }

Answer 2

myArray[0][0] thats how you access elements of two dimensional array. myArray[0] is enough for one dimensional array.

So, you should parse the numbers out of myArray[0] and myArray[1] and compares them instead.

Answer 3

here is your problem. in your main , notice the one dimension array?

public static void main(String [] myArray) 

In your body, you are accessing it as 2D array.

if((myArray[0][0]) < (myArray[0][1])){
    System.out.println("Minimum number is : " + myArray[0][0]);
    }

By default ,The main method accepts a single argument: an array of elements of type String. I am assuming that you actually meant to access the string from myArray ( as single dimension array) and proceed accordingly.

Also refer this if needed: http://docs.oracle.com/javase/tutorial/getStarted/application/index.html

Answer 4

命令行采用的参数是字符串类型，首先需要将它们转换为整数或浮点数以进行数字比较。