Javascript：Math.random

Question

If num parameter is 52, how many possible return values are there? is it 52 or 53? If I understand this correctly, Math.random uses random values from 0 to 1 inclusive. If so, then 0 is a possible return value and so is 52. This results in 53 possible return values. Is this correct? Reason I ask is that a book that I'm learning from uses this code for a deck of cards. I wonder if num should equal 51 ?

Thanks ...

function getRandom(num) {
    var my_num = Math.floor(Math.random * num);
    return my_num;
};

Answer 1

Math.floor(Math.random() * num) // note random() is a function.

This will return all integers from 0 (including 0) to num (NOT including num ).

Math.random returns a number between 0 (inclusive) and 1 (exclusive). Multiplying the result by X gives you between 0 (inclusive) and X (exclusive). Adding or subtracting X shifts the range by +-X.

Here's some handy functions from MDN :

// Returns a random number between 0 (inclusive) and 1 (exclusive)
function getRandom() {
  return Math.random();
}

// Returns a random number between min and max
function getRandomArbitrary(min, max) {
  return Math.random() * (max - min) + min;
}

// Returns a random integer between min and max
// Using Math.round() will give you a non-uniform distribution!
function getRandomInt(min, max) {
  return Math.floor(Math.random() * (max - min + 1)) + min;
}

Answer 2

Since Math.random returns a real number between [0,1) ( 1 is not inclusive), multiplying the result returns a real number between [0, 52) .

Since you are flooring the result, the maximum number returned is 51 and there are 52 distinct values (counting 0 ).

Answer 3

Since value of Math.random varies from 0 to 1(exclusive); so if you pass 52 in getRandom, return value will vary from 0 to 52(exclusive). so getRandom can return only 52 values. as you are using Math.floor. the max value can be returned is 51.