如何在所有操作系统上用 Python 解压缩文件？

Question

Is there a simple Python function that would allow unzipping a .zip file like so?:

unzip(ZipSource, DestinationDirectory)

I need the solution to act the same on Windows, Mac and Linux: always produce a file if the zip is a file, directory if the zip is a directory, and directory if the zip is multiple files; always inside, not at, the given destination directory

How do I unzip a file in Python?

Answer 1

Use the zipfile module in the standard library:

import zipfile,os.path
def unzip(source_filename, dest_dir):
    with zipfile.ZipFile(source_filename) as zf:
        for member in zf.infolist():
            # Path traversal defense copied from
            # http://hg.python.org/cpython/file/tip/Lib/http/server.py#l789
            words = member.filename.split('/')
            path = dest_dir
            for word in words[:-1]:
                while True:
                    drive, word = os.path.splitdrive(word)
                    head, word = os.path.split(word)
                    if not drive:
                        break
                if word in (os.curdir, os.pardir, ''):
                    continue
                path = os.path.join(path, word)
            zf.extract(member, path)

Note that using extractall would be a lot shorter, but that method does not protect against path traversal vulnerabilities before Python 2.7.4. If you can guarantee that your code runs on recent versions of Python.

Answer 2

Python 3.x use -e argument, not -h.. such as:

python -m zipfile -e compressedfile.zip c:\output_folder

arguments are as follows..

zipfile.py -l zipfile.zip        # Show listing of a zipfile
zipfile.py -t zipfile.zip        # Test if a zipfile is valid
zipfile.py -e zipfile.zip target # Extract zipfile into target dir
zipfile.py -c zipfile.zip src ... # Create zipfile from sources