[英]C++ template class compilation error
I get the following compilation error: 我收到以下编译错误:
main.cc: In function 'int main(int, char**)':¶
main.cc:200: error: no match for 'operator==' in 'rt1 == rt2'¶
triple.hh:124: note: candidates are: bool Triple<T1, T2, T3>::operator==(const Triple<T1,T2, T3>&) [with T1 = int, T2 = int, T3 = int] <near match>¶
main.cc:27: note: bool operator==(const Special&, const Special&)¶
Although I have implemented the operator== overload as follows for my template class: 尽管我为模板类实现了operator ==重载,如下所示:
bool operator==(const Triple<T1, T2, T3>& another) {
return (a == another.first() and b == another.second() and c == another.third());
}
For my template class: 对于我的模板类:
template <typename T1, typename T2, typename T3>
class Triple
Do you know what the problem might be? 您知道可能是什么问题吗? Many thanks.
非常感谢。
Your boolean operator is declared as non-const. 您的布尔运算符被声明为非常量。 Fix it as follows in case
rt1
is a const reference. 如果
rt1
是const引用,请按以下所示进行修复。 Note the added const
keyword. 请注意添加的
const
关键字。
bool operator==(const Triple<T1, T2, T3>& another) const {
Explanation: C++ has two basic syntaxes for overloading a comparison operator; 说明:C ++有两种用于重载比较运算符的基本语法: a member operator with one other argument, or a static operator with two arguments.
一个成员运算符带有另一个参数,或者是一个静态运算符带有两个参数。 However, in both cases, you should make sure that both operands are
const
, with the respective syntaxes. 但是,在两种情况下,都应确保两个操作数均为
const
,并具有各自的语法。
It is theoretically possible to supply different const
and non- const
versions of the operator that do subtly different things, so the compiler calls yours a near-match, but nevertheless not a match. 从理论上讲,可以提供不同的
const
版本和非const
版本的运算符来完成不同的事情,因此,编译器将您的匹配结果称为“接近匹配”,但仍不匹配。
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