获取数组中返回的最后一个URL

Question

I am using a form field to let a user edit a post and upload a profile image.

Once they upload the profile image a URL is passed to a hidden custom text field called 'logo_header'. I read this URL in the PHP template and use it to display the image as follows.

<?php $logo = get_post_meta($post->ID, 'logo_header', true); ?>

<div class="profileLogo"><img src="<?php echo $logo; ?>" /></div>

My Problem is when a user decides to update their photo (basically change the photo) the new URL is just added to the end of the current one, I guess this creates an array. so it would be like

http://example.com/myprofile.jpg , http://example.com/myprofile2.jpg

Obviously the image src cannot use an array, it needs 1 URL.

I use gravity forms upload file button to edit the post and upload the image. There is no option to delete the current image that already exists (Thats another problem :( ) so the user is only given an upload button.

My question is

How can I always choose the last URL added to the 'logo_header' field?

Answer 1

Try $logo = array_pop(get_post_meta($post->ID, 'logo_header', false));

With the false parameter, you'll get an array of all the meta fields. We can only assume that they'll be inserted and returned in the correct order, so array_pop() will pull the last one in the list.

Edit - for cases where you don't always have multiple logos, you should use this:

$logo = get_post_meta($post->ID, 'logo_header', false);
$logo = is_array($logo) ? array_pop($logo) : $logo;

Answer 2

$logo = get_post_meta($post->ID, 'logo_header', true);

$logoImgSrc = is_array($logo) ? end($logo) : $logo;

<div class="profileLogo">
    <img src="<?php echo $logoImgSrc ; ?>" />
</div>

Answer 3

I think you shouldn't be using a hidden text field, rather a hidden input field, when the user selects the new image (the files change() function, in jQuery) set the hidden field value to the new url, replacing the old, then post the hidden field name.

Edit to possibly help:

$("#browse_box").change(function() {
    $("#hidden_field").val($(this).val());
});

Typing from memory, but that would be the basic idea.