[英]Python variable won't change?
I'm making a game in python, and I have some code set up as such: 我正在用python做游戏,并且我设置了一些代码,例如:
istouching = False
death = True
def checkdead():
if istouching:
print "Is touching"
death = True
while death is False:
print death
game logic
I know the game logic is working, because "Is touching" prints, but then when I print out the value of death, it remains false, any help? 我知道游戏逻辑在起作用,因为“正在触摸”打印出来了,但是当我打印出死亡的价值时,它仍然是错误的,有什么帮助吗?
use global
to change global variables inside a function, otherwise death=True
inside checkdead()
will actually define a new local variable. 使用
global
来更改函数内部的全局变量,否则, checkdead()
内部的death=True
实际上将定义一个新的局部变量。
def checkdead():
global death
if istouching == True: #use == here for comparison
print "Is touching"
death = True
Make checkdead
return a value: 使
checkdead
返回一个值:
def checkdead():
if istouching:
print "Is touching"
return True
death = checkdead()
You could also use global
, as @AshwiniChaudhar shows, but I think it is preferable to write functions that return values instead of functions that modify globals, since such functions can be unit-tested more easily, and it makes explicit what external variables are changed. 您也可以使用
global
,如@AshwiniChaudhar所示,但我认为最好编写返回值的函数,而不是修改全局变量的函数,因为这样的函数可以更容易地进行单元测试,并且可以明确指出要更改的外部变量。
PS. PS。
if istouching = True
should have resulted in a SyntaxError since you can not make a variable assignment inside a conditional expression. if istouching = True
应该导致SyntaxError,因为您不能在条件表达式中进行变量赋值。
Instead, use 相反,使用
if istouching:
That's scope-related. 这与范围有关。
death = False
def f():
death = True # Here python doesn't now death, so it creates a new, different variable
f()
print(death) # False
death = False
def f():
global death
death = True
f()
print(death) # True
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.