Java String.split无法正常工作

Question

I have a string in following format:

CT-d0712728-867d-4cc4-bd0c-b2a679b8385f~#$~2012-10-16 02:13:27 PM

Can I use String.split("~#$~") or do I have to use StringTokenizer? I will have ONLY 2 parameters in above string, that's why I was trying to use String.Split("~#$~") but it doesn't seem to work.

Answer 1

$ is special character in regex (it means "end of a line"). To make it simple literal you need to escape it, for example with

• "\\\\$" ,
• "[$]"
• or using quotations "\\\\Q$\\\\E" .

Answer 2

Since split() method takes the paremeters as Regex , and $ is special meta-character in Regex . You need to escape the $ sign: -

    System.out.println(str.split("~#\\$~")[0]);
    System.out.println(str.split("~#\\$~")[1]);

Answer 3

try

String s = "CT-d0712728-867d-4cc4-bd0c-b2a679b8385f~#$~2012-10-16 02:13:27 PM";

Arrays.toString(s.split("~#\\$~"))

Answer 4

String str = "CT-d0712728-867d-4cc4-bd0c-b2a679b8385f~#$~2012-10-16 02:13:27 PM";
String[] pieces = str.split("~#\\$~");

Answer 5

you can do this using String.split(). No need to use StringTokenizer. See then below example.

String s="CT-d0712728-867d-4cc4-bd0c-b2a679b8385f~#$~2012-10-16 02:13:27 PM";
        String test[]=s.split("\\~\\#\\$\\~");
        System.out.println(test[0]);
        System.out.println(test[1]);

Let me know i you have any questions.