使用正则表达式验证日期

Question

I need a regex to pattern match the following -

mm/dd/yyyy

The following date entries should pass validation:

• 05/03/2012
• 5/03/2012
• 05/3/2012
• 5/3/2012

Also, after validating above regex , what is the best way convert above date string to Date object?

Answer 1

You should do the check and the parsing in one go, using split, parseInt and the Date constructor :

function toDate(s) {
  var t = s.split('/');
  try {
     if (t.length!=3) return null;
     var d = parseInt(t[1],10);
     var m = parseInt(t[0],10);
     var y = parseInt(t[2],10);
     if (d>0 && d<32 && m>0 && m<13) return new Date(y, m-1, d);
  } catch (e){}
}

var date = toDate(somestring);
if (date) // ok
else // not ok

DEMONSTRATION :

01/22/2012 ==> Sun Jan 22 2012 00:00:00 GMT+0100 (CET)
07/5/1972 ==> Wed Jul 05 1972 00:00:00 GMT+0100 (CEST)
999/99/1972 ==> invalid

As other answers of this page, this wouldn't choke for 31 in February. That's why for all serious purposes you should instead use a library like Datejs .

Answer 2

This one should do it:

((?:[0]?[1-9]|[1][012])[-:\\/.](?:(?:[0-2]?\\d{1})|(?:[3][01]{1}))[-:\\/.](?:(?:[1]{1}\\d{1}\\d{1}\\d{1})|(?:[2]{1}\\d{3})))(?![\\d])

(It is taken from txt2re.com)

You should also take a look at this link .

Answer 3

"/^(0?[1-9]|[12][0-9]|3[01])[\/\-](0?[1-9]|1[012])[\/\-]\d{4}$/"

链接： JavaScript日期正则表达式DD / MM / YYYY

Answer 4

var dateStr = '01/01/1901',
    dateObj = null,
    dateReg = /^(?:0[1-9]|1[012]|[1-9])\/(?:[012][1-9]|3[01]|[1-9])\/(?:19|20)\d\d$/;
    //             01 to 12 or 1 to 9   /    01 to 31  or  1 to 9   /  1900 to 2099

if( dateStr.match( dateReg ) ){
    dateObj = new Date( dateStr ); // this will be in the local timezone
}