[英]PHP regular expression match first occurrences?
http://someurlhere.com|http://sometexturl.com|sometexthere
i want to extract only the first url which is before the | 我想只提取在|之前的第一个网址 , http://someurlhere.com
, http://someurlhere.com
i have written regular expression 我写了正则表达式
\bhttp(.*)\|\b
but its capture all the occurences of | 但它捕获了所有出现的
Thanx help is appreciated Thanx帮助表示赞赏
Make the .*
ungreedy : .*?
制作
.*
ungreedy: .*?
\bhttp(.*?)\|\b
If you want to match only after the first |
如果你想只在第一个
|
之后匹配 do: 做:
\|http://(.*?)\|
with this, the url is in $1
有了这个,网址是
$1
This isn't a exact answer, but I will point you towards information that help you solve this issue! 这不是一个确切的答案,但我会指出您的信息,以帮助您解决这个问题!
Regex: matching up to the first occurrence of a character 正则表达式:匹配第一次出现的字符
No need for regex. 不需要正则表达式。 I see you tagged it PHP.
我看到你把它标记为PHP。
$boom = explode('|', 'http://someurlhere.com|sometexturl.com|sometexthere');
$url = $boom[0];
echo $url;
Output: 输出:
http://someurlhere.com
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.