以编程方式检查运行时是否存在Linux内核模块

Question

I am writing a C daemon, which depends on the existence of two kernel modules in order to do its job. The program does not directly use these (or any other) modules. It only needs them to exist. Therefore, I would like to programmatically check whether these modules are already loaded or not, in order to warn the user at runtime.

Before I start to do things like parsing /proc/modules or lsmod output, does a utility function already exist somewhere? Something like is_module_loaded(const char* name) ;

I am pretty sure this has been asked before. However, I think I am missing the correct terms to search for this.

Answer 1

There is no such function. In fact, the source code of lsmod ( lsmod.c ) has the following line in it which should lead you to your solution:

file = fopen("/proc/modules", "r");

There is also a deprecated query_module but it appears to only exist in kernel headers these days.

Answer 2

You can use popen and lsmod | grep lsmod | grep trick:

  FILE *fd = popen("lsmod | grep module_name", "r");

  char buf[16];
  if (fread (buf, 1, sizeof (buf), fd) > 0) // if there is some result the module must be loaded
    printf ("module is loaded\n");
  else
    printf ("module is not loaded\n");