获取 STL 向量中大于某个值的元素的所有位置

Question

I would like to know how can I find the index positions of elements that verify a certain condition (for example greater than). For example if I have a vector of int values

vector<int> V;

V contains the values 3 2 5 8 2 1 10 4 7

and I want to get all the index positions of elements that are greater than 5. I know std::find_if but according to the documentation it just finds the first element that satisfies a condition.

Answer 1

Loop std::find_if , starting from where you stopped last time.

Sample ( see it work ):

std::vector<size_t> results;

auto it = std::find_if(std::begin(v), std::end(v), [](int i){return i > 5;});
while (it != std::end(v)) {
   results.emplace_back(std::distance(std::begin(v), it));
   it = std::find_if(std::next(it), std::end(v), [](int i){return i > 5;});
}

First we set up the iterator with the first result. If it's not found, the while loop never executes. Otherwise, the index position is stored ( std::distance is basically a more generic it - std::begin(v) ), and the search continues onward.

Answer 2

I think I'd use std::copy_if :

std::vector<int> x{3, 2, 5, 8, 2, 1, 10, 4, 7};
std::vector<size_t> y(x.size());

std::iota(y.begin(), y.end(), 0);
std::copy_if(y.begin(), y.end(), 
             std::ostream_iterator<size_t>(std::cout, " "), 
             [&](size_t i) { return x[i] > 5; });

For me, this gives 3 6 8 , the indices of 8, 10 and 7 in x -- exactly what we want.

If you're stuck with a C++98/03 compiler/library, you'll use std::remove_copy_if instead (and reverse the sense of the comparison). In this case, you obviously won't be able to use a lambda for the comparison either.

Answer 3

Just for fun, transform_if algorithm:

#include <vector>
#include <iterator>
#include <algorithm>
#include <iostream>

template<typename InputIterator, typename OutputIterator,
    typename UnaryPredicate, typename UnaryFunction>
OutputIterator
transform_if (InputIterator first, InputIterator last,
    OutputIterator result, UnaryPredicate pred,
    UnaryFunction func)
{
    for (; first != last; ++first, ++result)
        if (pred(*first))
            *result = func(*first);
    return result;
}

int main()
{
    std::vector<int> x {3, 2, 5, 8, 2, 1, 10, 4, 7};
    std::vector<size_t> indices;

    size_t index = 0;
    transform_if(x.begin(), x.end(), std::back_inserter(indices),
        [&](int i){ return ++index, i > 5; },
        [&](int){ return index-1; });

    std::copy(indices.begin(), indices.end(),
              std::ostream_iterator<size_t>(std::cout, " "));
}

Output: 3 6 8

Answer 4

In C++20, with view, you might do

std::ranges::iota_view{0, (int)v.size()}
    | std::ranges::views::filter([&v](int i){ return v[i] > 5; })

Demo