具有多个具有不同签名的实现类的Java接口

Question

I am creating an interface say 'Car'

public interface Car {
    public void drive(int Speed, int Gear ); // for cars which have gears
    public void drive(int Speed); // for cars which do not have gears
}

Now i am creating my implimentation classes say SimpleCar and AdvanceCar where

• SimpleCar do not have gears
• AdvanceCar have gears

Now when i write my implementation classes i am forced to code for both the methods even though i do not want them in my implementation classes

public class SimpleCar implements Car {
    public void drive(int Speed, int Gear ){ ... }; // dont want this method in SimpleCar
    public void drive(int Speed ){ ... };
}

can someone help me design my interface which has a method but the implementation classes have different signatures?

Answer 1

public interface Car {

    public void drive(int Speed, int Gear); // for cars which have gears

    public void drive(int Speed); // for cars which do not have gears
}



public class CarAdapter implements Car {

    @Override
    public void drive(int Speed, int Gear) {
        // TODO Auto-generated method stub

    }

    @Override
    public void drive(int Speed) {
        // TODO Auto-generated method stub

    }

}


public class AdvancedCar extends CarAdapter {

    @Override
    public void drive(int Speed) {
        // TODO Auto-generated method stub
        super.drive(Speed);
    }

    @Override
    public void drive(int Speed, int Gear) {
        // TODO Auto-generated method stub
        super.drive(Speed, Gear);
    }

}


public class SimpleCar extends CarAdapter {

    @Override
    public void drive(int Speed) {
        // TODO Auto-generated method stub
        super.drive(Speed);
    }


}

Answer 2

You should have a Car interface and another one named GearCar interface which extends Car interface.

This way you can either implement GearCar or Car interface.

Answer 3

See following design. I've removed gear from Car interface cause based on your requirements it's not valid for all cars and hence can't be part of interface.

public interface Car 
{     
    // public void drive(int Speed, int Gear ); // for cars which have gears     
    public void drive(int Speed); // for cars which do not have gears 
}

public abstract class SimpleCar implements Car
{
    public void drive(int speed) { ... }
    public abstract void accelerate(); // you can move it to interface also
}

public abstract class AdvancedCar implements Car
{
    protected int CURRENT_GEAR = 1;
    public void drive(int speed) { ... }
    public void changeGear(int gear) { ... }
    public abstract void accelerate();
}

public class Reva extends SimpleCar
{
    // provide implementation for accelerate
}

public class Ferrari extends AdvancedCar
{
    // provide implementation for accelerate
}

Answer 4

Write an CarAdapter providing empty implementations of all methods in the interface. Then let your SimpleCar extend CarAdapter (which by default implements Car )

This is frequently seen in Swing applications.

Answer 5

Just remove the method declaration that needs Gear because in your class you need to implement every method declared in the interface that you are implementing unless your class itself is abstract.

Also you should have your SimpleCar and AdvancedCar as abstract class if you don't want to implement any methods of the interface.

Answer 6

public interface Vehicle {
    public void drive(int Speed);
}

public interface Car extends Vehicle{
    public void drive(int Speed, int Gear ); 
}

public class SimpleCar implements Vehicle {
    public void drive(int Speed ){ ... };
}

public class AdvancedCar implements Car {
    public void drive(int Speed, int Gear ){ ... };
    public void drive(int Speed ){ ... };
}