[英]Compiler warning when using boost::blank in a boost::variant
I'm getting a warning for the following code, which dissapears if I remove boost::blank from the variant: 我收到以下代码的警告,如果我从变体中删除boost :: blank,该代码将消失:
namespace DB
{
struct Value{};
struct Container{};
}
typedef boost::variant <boost::blank, DB::Value, DB::Container> CommandData;
struct Command {
explicit Command(CommandData& _data): data(_data){
}
CommandData data;
};
int main()
{
CommandData commandData;
Command command(commandData);
return 0;
}
What's this issue? 这是什么问题
Here's the warning: 这是警告:
1>: warning C4345: behavior change: an object of POD type constructed with an initializer of the form () will be default-initialized
1> c:\boost_1_49_0\boost\variant\variant.hpp(1224) : while compiling class template member function 'boost::variant<T0_,T1,T2>::variant(void)'
1> with
1> [
1> T0_=boost::blank,
1> T1=DB::Value,
1> T2=DB::Container
1> ]
1> c:\code.h(38) : see reference to class template instantiation 'boost::variant<T0_,T1,T2>' being compiled
1> with
1> [
1> T0_=boost::blank,
1> T1=DB::Value,
1> T2=DB::Container
1> ]
That warning is rather dumb. 该警告相当愚蠢。 It warns that MSVC now does the right thing as opposed to some ancient version.
它警告说,MSVC现在做正确的事情,而不是某些古老版本。 You can turn it off with a
pragma
. 您可以使用
pragma
程序将其关闭。
It's not because of the variant. 这不是因为变体。 Try to put int as a struct member for example instead of variant, and you'll get the same warning.
例如,尝试将int作为结构成员而不是variant,您将得到相同的警告。 The thing is that variant initializes with the first value by default, and boost::blank is a spectial type to optimize the variant behavior.
问题在于,默认情况下,变量会使用第一个值进行初始化,而boost :: blank是用于优化变量行为的特殊类型。 See the variant documentation in Boost
请参阅Boost中的变体文档
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