在mysql join，union> =和<=中计算符合条件的行

Question

Select * FROM table WHERE a<=9 AND a>=4 AND b<=20 AND b>=16 AND c<=30 AND c>=26

Now I want to end up selecting from query 1 the results in which at least two of the following criteria are met.

Select * FROM table WHERE a<=7 AND a>=5 AND B<=19 AND B>=17 AND C<=29 AND c>=27

Numbers could be anything, although on query 2 these are lower for the less than eqaul and higher for the bigger than equal.

I want to be able to set the number of minimum coincidences to be met at query 2 with a number. For example 5 coincidences must be met at query 2 to end up making a selection in query 1.

This is about range and matches count, if there is an easier way to achieve this great.

Answer 1

尝试使用本机MySQL函数BEETWEN ：

SELECT * FROM t1 WHERE key_col BETWEEN '2' AND '3';

Answer 2

Think it is something like this you want for the second query:-

Select *, CASE WHEN a<=7 THEN 1 ELSE 0 END + CASE WHEN  a>=5 THEN 1 ELSE 0 END + CASE WHEN B<=19 THEN 1 ELSE 0 END + CASE WHEN B>=17 THEN 1 ELSE 0 END + CASE WHEN C<=29 THEN 1 ELSE 0 END + CASE WHEN c>=27 THEN 1 ELSE 0 END AS MatchCount
FROM table 
WHERE a<=7 
OR a>=5 
OR B<=19 
OR B>=17 
OR C<=29 
OR c>=27
HAVING MatchCount >= 2

Probably using the first query as a subselect instead of table.

EDIT - reading your latest response I think I misunderstood your requirement. However you could possibly find the differences between each values, get the absolute value of each difference and add them together to see how close / far the differences are.

Answer 3

i think this kind of query will do your job

Select 
*,
(IF(a<=7 AND a>=5,1,0) + IF(B<=19 AND B>=17,1,0) + IF(C<=29 AND c>=27,1,0))
as totalmatch
FROM table
HAVING totalmatch >=2