[英]JQuery selectors don't work
I have the following input on my page: 我的页面上有以下输入:
<input type="text" name="r1" />
I am trying to select it with JQuery, using $("[name='r1']")
, and for some reason it returns null
. 我试图用JQuery选择它,使用
$("[name='r1']")
,并且由于某种原因它返回null
。 Ok, fine, the title is misleading in that it is me that is doing something wrong; 好吧,很好,标题是误导性的,因为我做错了; can you tell me what?
你能告诉我什么吗?
EDIT: 编辑:
$('input[name="r1"]')
doesn't work either. $('input[name="r1"]')
也不起作用。 Also, sorry for the typo. 另外,抱歉打字错误。
Html Code Html代码
<input type="text" name="r1" />
Jquery Code Jquery代码
$(document).ready(function() {
alert($('input[name="r1"]').length);
});
OLD Updates 旧更新
you have typo error here you are trying to find r2
element which is not there just update code like $("[name='r1']")
你有拼写错误在这里,你试图找到
r2
元素,这不只是更新代码,如$("[name='r1']")
or 要么
to find it proper way you should do as below 找到你应该做的正确方法如下
$("input[name='r2']")
instead of $("[name='r2']")
only $("input[name='r2']")
而不是$("[name='r2']")
EDIT 编辑
According to you edited question you should check example over here : Attribute Equals Selector [name="value"] 根据您编辑的问题,您应该检查此处的示例: 属性等于选择器[name =“value”]
EDIT 编辑
for proper check you can do like this 为了正确检查你可以这样做
$(document).ready(function() {
alert($('input[name="r1"]').length);
});
Just made a quick test: 刚做了一个快速测试:
<input type="text" name="r1" />
with the following Javascript 使用以下Javascript
$('input[name=r1]').click(function(e){
alert('found');
});
It worked perfectly! 它工作得很好!
You are not telling jQuery what element you're looking for, that is you input
你没有告诉jQuery你正在寻找什么元素,那就是你
input
Try doing it this way 尝试这样做
$('input[name=r1]')
它肯定会起作用:
$("*[name='r1']")
You can use both $("[name='r1']")
and $('input[name="r1"]')
in this scenario 您可以在此场景中同时使用
$("[name='r1']")
和$('input[name="r1"]')
Use $("[name='r1']")
if you want to select any element with attribute called " name " equal to " r1 " 如果要选择名为“ name ”的属性等于“ r1 ”的任何元素,请使用
$("[name='r1']")
Use $('input[name="r1"]')
if you want to select only input elements with attribute called " name " equal to " r1 " 如果要仅选择名为“ name ”的属性等于“ r1 ”的输入元素,请使用
$('input[name="r1"]')
More JQuery Attribute fillter examples are listed here 此处列出了更多JQuery Attribute fillter示例
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