无法执行查询

Question

Can somebody help me with this query.The page doesn't load up whenever i run this query.I'm pretty much sure its something really simple mistake which I'm unable to figure out.Your help is much appreciated.

$aggr_nr = $_REQUEST['stck_list_nr_01'].$_REQUEST['stck_list_nr_02'].$_REQUEST['stck_list_nr_03'];
echo $aggr_nr;

$sql="SELECT v.id FROM vers_einl_aggregatnummer AS v WHERE v.aggr_nr = $aggr_nr";
$aggr_id = mysql_query($sql);

if ($aggr_id == true)
 {
        echo "query 1 executed".$aggr_id;
    else  
    {
    echo("<br />Could not execute statement ".$sql);
    }
 }

Answer 1

there was a syntax error look at this

if ($aggr_id != false)//since on success resource type is returned.
{
 echo "query 1 executed".$aggr_id;
}else  
{
  echo("<br />Could not execute statement ".$sql);
 }

also

$aggr_nr = $_REQUEST['stck_list_nr_01'].$_REQUEST['stck_list_nr_02'].$_REQUEST['stck_list_nr_03'];
echo $aggr_nr;
if(isset($aggr_nr)&&is_numeric($aggr_nr))
{
$aggr_nr=mysql_real_escape_string($aggr_nr);

$sql="SELECT v.id FROM vers_einl_aggregatnummer AS v WHERE v.aggr_nr = $aggr_nr";
$aggr_id = mysql_query($sql);
}

Answer 2

//sanitize the inputs 
$aggr_nr = mysql_real_escape_string($_REQUEST['stck_list_nr_01'].$_REQUEST['stck_list_nr_02'].$_REQUEST['stck_list_nr_03']);
 echo $aggr_nr;

$sql="SELECT v.id FROM vers_einl_aggregatnummer AS v WHERE v.aggr_nr = '".$aggr_nr."'";//missing Quotes
$aggr_id = mysql_query($sql);

if ($aggr_id) {
 while($result = mysql_fetch_array($aggr_id))
   echo "ID NUMBER:".$result['id'];
}  else {
   echo "<br />Could not execute statement ".$sql;
}

Answer 3

Just a word about PHP errors not showing ( page doesn't load up ).

You can configure PHP to stop on errors and not show it. This should be the default setting on a production server to not show too much internal information in case of an error.

You can use these lines to display all the errors, but don't forget to turn it off again ;)

ini_set('display_errors', 1);
error_reporting(E_ALL);