等待功能完成

Question

I have 2 functions. The second one is faster than the first one,how could the function wait to complete first one's work?

function1(); // slow 

function2(); // fast

Answer 1

JavaScript is imperative and single-threaded, it just works like this. function2() won't start until function1() finishes.

If by slow you mean calling asynchronously some external service via AJAX, then we're talking. function1() must provide some sort of callback so that when asynchronous request finishes, function2() is called:

function1(function2);

The implementation is trivial, eg using jQuery:

function function1(callback) {
  $.ajax({url: 'some-url'}).done(callback);
}

Answer 2

You must be using some AJAX request. So, after ajax complete call callback function like:

function1 = new function(callback) {
    $.ajax({...}).done(callback());
}

function1(function2);

Answer 3

If functions are to be called asynchronously, aside from the obvious callback approach, their sequencing could be based on the events framework. You could add an event listener with function1 as a handler, and trigger that event within function2.

Answer 4

如果你的呼叫功能接着另一个，则它将完成第一个功能，无论是慢速还是快速。