电话号码的正则表达式（JS）

Question

How to write a regular expression to take +Z (YYY) XXX-XX-XX , and get YYYXXXXXXX ? This is for phone number.

Answer 1

you can do this by

var mobile = "+Z (567) 567-567-567";
  var n=mobile.replace("(","");
 n =n.replace(/[^0-9]+/g, ''); 

alert(n)​

jSfiddle

Answer 2

if you have exact the format +Z (YYY) XXX-XX-XX :

var num = input.replace( '/^\+\S+\s\((\d{3})\)\s(\d{3})-(\d{2})-(\d{2})$/', '\1\2\3\4' );

but a more tolerant variant would be

var num = input.replace( '/^(\+\S+|\D/', '' );