[英]Javascript RegEx to match words without preceding or trailing hyphens
I need a RegEx for Javascript which will match the string "smith" in lines 1-4 but not in lines 5-8 below.我需要一个 Javascript 的正则表达式,它将匹配第 1-4 行中的字符串“smith”,但不匹配下面的第 5-8 行。
The numbered lines are fields in an Access database (the fields do not contain the numbers).编号的行是 Access 数据库中的字段(字段不包含数字)。
What I have so far is:到目前为止,我所拥有的是:
var xy = 'smith';
MyString = new RegExp('(^|\\W)' + xy + '(\\W|$)', 'i');
This matches the Smiths in lines 1-4, but also those in Lines 7 and 8.这与第 1-4 行中的 Smiths 匹配,也与第 7 行和第 8 行中的 Smiths 匹配。
How can I get the expression to also ignore the Smiths which are preceded or followed by a hyphen?我怎样才能让表达式也忽略前面或后面有连字符的 Smiths?
After a week and dozens of attempts, I am asking the experts经过一周和几十次尝试,我在问专家
Write the negative character class ( \W
) yourself and include the hyphen:自己写否定字符 class (
\W
) 并包括连字符:
MyString = new RegExp('(^|[^a-z0-9_-])' + xy + '([^a-z0-9_-]|$)', 'i');
While \W
matches any non-word character (everything but letters, digits and underscores), [^a-z0-9_-]
matches any character that is neither such a word character nor a hyphen. \W
匹配任何非单词字符(除了字母、数字和下划线之外的所有字符),而[^a-z0-9_-]
匹配任何既不是单词字符也不是连字符的字符。
You could of course use \w
within that character class:您当然可以在该字符 class 中使用
\w
:
MyString = new RegExp('(^|[^\\w-])' + xy + '([^\\w-]|$)', 'i');
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