[英]Drawing a Control Flow Graph
My task is to make a control flow graph. 我的任务是制作一个控制流程图。 First, I have managed to seperate my code into basic blocks.
首先,我设法将我的代码分成基本块。 For example, this program here:
例如,这个程序在这里:
1 begin
2 int x, y, power;
3 float z;
4 input (x, y);
5 if (y<0)
6 power=-y;
7 else
8 power=y;
9 z=1;
10 while (power!=0){
11 z=z*x;
12 power=power-1;
13 }
14 if (y<0)
15 z=1/z;
16 output(z);
17 end
will turn into the following basic blocks: 将变成以下基本块:
BLOCK 1 第1块
Line 2 int x, y, power;
Line 3 float z;
Line 4 input (x, y);
Line 5 if (y<0)
BLOCK 2 第2块
Line 6 power=-y;
BLOCK 3 第3块
Line 8 power=y;
BLOCK 4 第4块
Line 9 z=1;
BLOCK 5 第5块
Line 10 while (power!=0){
BLOCK 6 第6块
Line 11 z=z*x;
Line 12 power=power-1;
BLOCK 7 第7块
Line 14 if (y<0)
BLOCK 8 第8块
Line 15 z=1/z;
BLOCK 9 第9块
Line 16 output(z);
I have done this by scanning through the file, and using Pattern and Matcher to split the program up based on if, while, etc statements. 我通过扫描文件,并使用Pattern和Matcher根据if,while,etc语句拆分程序来完成此操作。 The basic blocks are an ArrayList and all these blocks are kept in an ArrayList>.
基本块是ArrayList,所有这些块都保存在ArrayList>中。
Next, I have kept a HashMap of the which basic blocks are connected to each other. 接下来,我保留了一个HashMap,其中哪些基本块相互连接。 For example, block 1 will be connected to block 2 and block 3 as it is an if statement (if this go one way, else go the other).
例如,块1将连接到块2和块3,因为它是一个if语句(如果这是单向,否则去另一个)。 This HashMap is of > for the block number, and the list of block numbers that it is connected to.
这个HashMap是>用于块号,以及它所连接的块号列表。
So, I have the basic blocks, and a list of connections between these basic blocks. 所以,我有基本的块,以及这些基本块之间的连接列表。 My problem now is that I am not sure how to display this in a graphical form.
我现在的问题是我不确定如何以图形形式显示它。 Before, I was using the paint() method and drawing circles and lines to represent a simple control graph where each block only had one connection to the next block.
之前,我使用paint()方法并绘制圆和线来表示一个简单的控制图,其中每个块只有一个连接到下一个块。 However, I do not know how to do this when there are multiple connections.
但是,当有多个连接时,我不知道如何执行此操作。 Is there any easy way of doing this?
这有什么简单的方法吗?
Thanks! 谢谢!
为了绘制图形,我通常使用点 ,它非常直接。
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