[英]Parameter of method in interface (without generics)?
I'm completely stuck with my amateur project. 我完全被业余项目困住了。 I've got MySingleton that implements
MyInterface
and calls MyMethod()
. 我有MySingleton实现
MyInterface
并调用MyMethod()
。 MyMethod()
should take any of MySubcls
as a parameter. MyMethod()
应该采用MySubcls
中的任何一个作为参数。 The problem is how to declare MyMethod()
without generics? 问题是如何在没有泛型的情况下声明
MyMethod()
? Should use many declarations with differernt parameters or no way without generics? 应该使用带有不同参数的许多声明还是没有泛型的方法?
Main.java => need to print values of all subclasses from single method Main.java =>需要从单个方法打印所有子类的值
public class Main{
public static void main(String[] args){
MySubcls01 subCls01 = new MySubcls01();
MySubcls02 subCls02 = new MySubcls02();
MySingleton.INSTANCE.MyMethod(subCls01);
MySingleton.INSTANCE.MyMethod(subCls02);
}
}
enum MySingleton implements MyInterface
{
INSTANCE;
@Override
public void MyMethod();// TODO - need to pass subCls01 or subCls02
{
System.out.println(subCls01.value);
System.out.println(subCls02.value);
}
}
interface MyInterface
{
void MyMethod(); // TODO - what parameter for any subclass???
// void MyMethod(MySubcls01 subCls01);
// void MyMethod(MySubcls02 subCls02); => brute-force approach
// <T> void MyMethod(T type); => shouldn't use generics
}
class MySupercls
{
// some stuff
}
class MySubcls01 extends MySupercls
{
String subValue = "i'm from subclass01";
}
class MySubcls02 extends MySupercls
{
String subValue = "i'm from subclass02";
}
I think you need to use superclass type as parameter and use instanceof to determine real type. 我认为您需要使用超类类型作为参数,并使用instanceof来确定实型。
Example: 例:
@Override
public void MyMethod(MySupercls inst)// TODO - need to pass subCls01 or subCls02
{
if (inst instanceof MySubcls01)
{
//cast it subclass01
System.out.println(subCls01.value);
}else{
//cast it subclass02
System.out.println(subCls02.value);
}
}
Note: Your code has public void MyMethod();
注意:您的代码具有
public void MyMethod();
while implementing method. 在实施方法时。 You should remove semi-colon.
您应该删除分号。
使用超类作为参数,现在您可以将所有子类实例传递给myMethod()
public void MyMethod(MySuperClass yourInstance);// TODO - need to pass subCls01 or subCls02
If I understand your question correctly, you should be expecting a type common to both MySubcls01
and MySubcls02
, in this case MySupercls
. 如果我正确理解了您的问题,那么您应该期望
MySubcls01
和MySubcls02
都具有通用类型,在本例中为MySupercls
。
So, you should have MyMethod(MySupercls obj);
因此,您应该具有
MyMethod(MySupercls obj);
as your method signature. 作为您的方法签名。
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