Javascript正则表达式可获取2个字符以及之间的所有字符

Question

I have a very basic understanding of Regex and am finding this difficult to achieve.

There is a html select with numerous options like this

<select>
  <option value="%001% 25cm Single" label="%001% 25cm Single">%001% 25cm Single</option>
  <option value="%002% 25cm Single" label="%002% 25cm Single">%002% 25cm Single</option>
  <option value="%003% 25cm Single" label="%003% 25cm Single">%003% 25cm Single</option>
</select>

%001%, %002% etc is going to be used to order the options, the opening % and closing % as well as the content between also needs to be hidden from the frontend. However, before any of this can be done the %xxx% neededs to be grabbed with regex.

So what is needed, it seems, is to match the first occurrence for each option of a string that starts with a %, followed by any 3 digits, followed by another %. The numbers between the % are what need to be returned for ordering

There also needs to be a regex rule that matches and returns both the % and the 3 numbers between then so that they can be hidden from the front end using jquery.

So far I have

/^%.{3}%/

All help appreciated

Answer 1

要获取％123％的零件，请使用： %[\\d]{3}%

Answer 2

In general, to find all characters up until another stop character, you can use either:

/[^%]+/ // One or more characters which are not a % character
/.+?%/  // One or more non-newline characters, as few as possible, up to a %

So, to find a % followed by anything up until the next % , you can use either:

/%[^%]+%/
/%.+?%/

However, if you know that there must always be exactly three digit characters, then you should use that (more restrictive) regex:

/%\d{3}%/

If you want to preserve any part of the match for separate reference, make it a "capture" by enclosing it in parentheses. Each capture will come out as a separate part of the array returned by String.prototype.match :

var marker = /%(\d{3})%/;
var string = "%001% 25cm Single";
var results = string.match(marker);
var number  = results && results[1]; // "001"