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将对象传递到另一个活动

[英]passing objects to another activity

原文 2012-10-30 14:05:18 7 2 android/ android-activity

Situation 情况

In my alarm clock app I start a NewAlarmActivity by clicking a button. 在我的闹钟应用程序中，我通过单击一个按钮来启动NewAlarmActivity 。 After the user has made all the selections, alarm gets set and `finish() is called. 用户做出所有选择之后，将设置警报并调用`finish（）。

The matter 这件事

I create a new LinearLayout object with images and text within it. 我创建一个新的LinearLayout对象，其中包含图像和文本。 That layout must be added to the screen of previous activity (to another LinearLayout placed inside a ScrollView ) so the user is able to see the alarm set. 该布局必须添加到上一个活动的屏幕上（放置在ScrollView内的另一个LinearLayout ），以便用户能够看到警报集。 Somehow I have to pass that LinearLayout object to the first activity and tell it to receive and add the object to the screen. 我必须以某种方式将那个LinearLayout对象传递给第一个活动，并告诉它接收该对象并将其添加到屏幕。

How can I do that? 我怎样才能做到这一点？

2 个解决方案

You just need to read some documentation about startActivityForResult() . 您只需要阅读一些有关startActivityForResult()文档。

BTW, IMHO, you should not transport your LinearLayout object between activities, that's ugly. 顺便说一句，恕我直言，您不应该在活动之间传输LinearLayout对象，这很丑陋。

How to manage `startActivityForResult` on Android? 如何在Android上管理`startActivityForResult`？

Starting Activity And Getting Result 开始活动并获得结果

This has been asked countless times... 这已经被问过无数次了...

No You don't have to do this. 不，您不必这样做。 Try the approach of storing your data into a database and then when going into that Activity, build your layout according to the data you have. 尝试将数据存储到数据库中的方法，然后在进入该活动时，根据您拥有的数据构建布局。 This is a much better way than passing a layout from one Activity to antoher. 与将布局从一个活动传递到另一个活动相比，这是一种更好的方法。