[英]Why does `Array.length`, `Function.length`, `String.length`, etc return 1?
While teaching my JavaScript class yesterday, my students and I came across some interesting functionality that I thought might be worth capturing in a question and the answer I've come to. 在昨天教我的JavaScript课程时,我和我的学生遇到了一些有趣的功能,我认为这些功能值得在一个问题和我得到的答案中捕获。
Typing Array.length
in the JS console in chrome returns 1
. 在chrome控制台
Array.length
chrome输入Array.length
返回1
。
Likewise, Function.length
returns 1
. 同样,
Function.length
返回1
。 This is important because: 这很重要,因为:
Every function in JavaScript is actually a Function object.
JavaScript中的每个函数实际上都是一个Function对象。 (MDN JS Ref: Function)
(MDN JS参考:功能)
Thus, Object.length
and likely all other native objects will and should return 1
as the value of the length
property. 因此,
Object.length
和可能所有其他本机对象将返回1
作为length
属性的值。
So, finally why is this behavior occurring? 那么,最后为什么会发生这种行为呢?
Function.length
itself is the answer: Function.length
本身就是答案:
Specifies the number of arguments expected by the function.
指定函数所需的参数数。 MDN JS Ref: Function.length
MDN JS Ref:Function.length
When we write Function.length
we are asking the Function
constructor to tell us the number of formal, named parameters ("optional" - ie non-formal - parameters are accessed via the arguments
property in the function body). 当我们编写
Function.length
我们要求Function
构造Function
告诉我们正式命名参数的数量(“可选” - 即非正式 - 参数通过函数体中的arguments
属性访问)。 Because the Function
constructor expects exactly 1 formal named parameter, the result is 1
: 因为
Function
构造Function
正好需要1个正式命名参数,所以结果为1
:
new Function ([arg1[, arg2[, ... argN]],] functionBody)
functionBody
is the single formal named parameter. functionBody
是单个正式命名参数。 Therefore Function.length
is 1
. 因此
Function.length
为1
。
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