[英]Symfony2: The CSRF token is invalid. Please try to resubmit the form
I have a form wher I have to fill in some information in a field. 我有一个表格,我必须在一个字段中填写一些信息。 Even if I put something inside, I am getting the error: 即使我把东西放进去,我也会收到错误:
The CSRF token is invalid. Please try to resubmit the form
Related to this question: symfony2 CSRF invalid I am using correctly the $form->bindRequest() 与此问题相关: symfony2 CSRF无效我正确使用$ form-> bindRequest()
if ($this->getRequest()->getMethod() == 'POST') {
$form->bindRequest($this->getRequest());
if ($form->isValid())
{
...
}
Here is my template (twig) code: 这是我的模板(twig)代码:
<div class="item item-last">
<h1>Create Affiliation</h1>
{% if valid == false %}
<div class="error">
{{ form_errors(form) }}
{{ form_errors(form.affiliation) }}
{{ error }}
</div>
{% endif %}
{% if app.session.flash('user-notice') != '' %}
<div class="flash-notice">
{% autoescape false %}
{{ app.session.flash('user-notice') }}
{% endautoescape %}
</div>
{% endif %}
</div>
<div class="item item-last">
<form action="{{ path('SciForumVersion2Bundle_user_submission_affiliation_create', {'hash_key' : submission.hashkey, 'author_id' : author.id }) }}?ajax=no" method="POST" class="authorForm" {{ form_enctype(form) }}>
<div style="float:left;">
<table width="100%" cellspacing="0" cellpadding="0">
<tr>
<td>
{{ form_label(form.affiliation) }}
</td>
<td>
{{ form_widget(form.affiliation, { 'attr': {'size': 40} }) }}
</td>
</tr>
<tr>
<td>
</td>
<td>
<div class="button button-left button-cancel">
<img src="{{ asset('bundles/sciforumversion2/images/design/new/button-red.png') }}"/>
<a href="{{ path('SciForumVersion2Bundle_user_submission_author_edit', { 'hash_key' : submission.hashkey, 'author_id' : 0 }) }}" class="submission_link">cancel</a>
</div>
<div style="float: left;"> </div>
<div class="button button-left button-cancel">
<img src="{{ asset('bundles/sciforumversion2/images/design/new/button.png') }}"/>
<input type="submit" name="login" value="submit" />
</div>
<div style="clear: both;"></div>
</td>
</tr>
</table>
</div>
{{ form_rest(form) }}
</form>
</div>
And here is the js code: 这是js代码:
function init_submission_functions()
{
init_fck();
$(".submission_link").unbind("click").bind("click", function() {
var href = $(this).attr("href");
if( href == null || href == '' ) return false;
$.ajax({
type: "POST",
async: true,
url: href,
cache: false,
dataType: "json",
success: function(data) {
$("#content .contentwrap .itemwrap").html( data.content );
init_submission_functions();
}
});
return false;
});
$(".authorForm").unbind("submit").bind("submit", function() {
var href = $(this).attr("action");
if( href == null || href == '' ) return false;
var affiliation = "blabla";
$.ajax({
type: "POST",
async: true,
url: href,
affiliation: affiliation,
cache: false,
dataType: "json",
success: function(data) {
$("#content .contentwrap .itemwrap").html( data.content );
init_submission_functions();
}
});
return false;
});
}
But I am still getting the same error. 但我仍然得到同样的错误。
Send a serialized form using the serialize
jQuery method : 使用serialize
jQuery方法发送序列化表单:
$form.submit(function (e) {
e.preventDefault();
$this = $(this);
$.post($this.attr('action'), $this.serialize(), function (response) {
// handle the response here
});
});
This way Symfony will handle the submit request as a normal request — you don't have to do anything special to handle an Ajax form submission. 这样,Symfony将作为正常请求处理提交请求 - 您无需执行任何特殊操作来处理Ajax表单提交。 All you'll need to do is to return a JsonResponse
— if you need it, of course. 您需要做的就是返回一个JsonResponse
- 当然,如果您需要它。
Here is an example of handling the form — adapt it to your needs: 以下是处理表单的示例 - 根据您的需求进行调整:
if ('POST' === $request->getMethod()) {
$form->bind($request);
if ($form->isValid()) {
// do something here — like persisting or updating an entity
return new JsonResponse([
'success' => true,
]);
}
return new JsonResponse([
'success' => false,
'form' => $this->render($pathToTheTemplateHere, [
'form' => $form,
],
]);
}
The other way would be to use different templates: form.json.twig
and form.html.twig
— read the docs for details. 另一种方法是使用不同的模板: form.json.twig
和form.html.twig
- 阅读文档以获取详细信息。
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