在文件IO中保留换行符和间距

Question

I am workig on a pretty neat problem challenge that involves reading words from a .txt file. The program must allow for ANY .txt file to be read, ergo the program cannot predict what words it will be dealing with.

Then, it takes the words and makes them their "Pig Latin" counterpart, and writes them into a new file. There are a lot more requirements to this problem but siffice to say, I have every part solved save one...when printng to the new file I am unable to perserve the line spacing. That is to say, if line 1 has 5 words and then there is a break and line 2 has 3 words and a break...the same must be true for the new file. As it stands now, it all works but all the converted words are all listed one after the other.

I am interested in learning this so I am OK if you all wish to play coy in your answers. Although I have been at this for 9 hours so "semi-coy" will be appreaciated as well :) Please pay close attention to the "while" statements in the code that is where the file IO action is happening. I am wondering if I need to utilize the nextLine() commands from the scanner and then make a string off that...then make substrings off the nextLine() string to convert the words one at a time. The substrings could be splits or tokens, or something else - I am unclear on this part and token attempts are giving me compiler arrors exceptions "java.util.NoSuchElementException" - I do not seem to understand the correct call for a split command. I tried something like String a = scan.nextLine() where "scan" is my scanner var. Then tried String b = a.split() no go. Anyway here is my code and see if you can figure out what I am missing.

Here is code and thank you very much in advance Java gods....

import java.util.*;
import javax.swing.*;
import java.io.*;
import java.text.*;

public class PigLatinTranslator
{
    static final String ay = "ay"; // "ay" is added to the end of every word in pig latin

    public static void main(String [] args) throws IOException
    {
        File nonPiggedFile = new File(...);
        String nonPiggedFileName = nonPiggedFile.getName();
        Scanner scan = new Scanner(nonPiggedFile);  

        nonPiggedFileName = ...;

        File pigLatinFile = new File(nonPiggedFileName + "-pigLatin.txt"); //references a file that may or may not exist yet

        pigLatinFile.createNewFile();
        FileWriter newPigLatinFile = new FileWriter(nonPiggedFileName + "-pigLatin.txt", true);
        PrintWriter PrintToPLF = new PrintWriter(newPigLatinFile);

        while (scan.hasNext()) 
        {
            boolean next;
            while (next = scan.hasNext()) 
            {
                 String nonPig = scan.next();
                 nonPig = nonPig.toLowerCase();
                 StringBuilder PigLatWord = new StringBuilder(nonPig);
                 PigLatWord.insert(nonPig.length(), nonPig.charAt(0) );
                 PigLatWord.insert(nonPig.length() + 1, ay);
                 PigLatWord.deleteCharAt(0);
                 String plw = PigLatWord.toString();

                 if (plw.contains("!") )
                 {
                     plw = plw.replace("!", "") + "!";
                 }

                 if (plw.contains(".") )
                 {
                     plw = plw.replace(".", "") + ".";
                 }

                 if (plw.contains("?") )
                 { 
                     plw = plw.replace("?", "") + "?"; 
                 }

                 PrintToPLF.print(plw + " ");
            }

            PrintToPLF.close();
        }
    }
}

Answer 1

Use BufferedReader , not Scanner . http://docs.oracle.com/javase/6/docs/api/java/io/BufferedReader.html

I leave that part of it as an exercise for the original poster, it's easy once you know the right class to use! (And hopefully you learn something instead of copy-pasting my code).

Then pass the entire line into functions like this: (note this does not correctly handle quotes as it puts all non-apostrophe punctuation at the end of the word). Also it assumes that punctuation is supposed to go at the end of the word.

private static final String vowels = "AEIOUaeiou";
private static final String punct = ".,!?";

public static String pigifyLine(String oneLine) {
   StringBuilder pigified = new StringBuilder();
   boolean first = true;
   for (String word : oneLine.split(" ")) {
       if (!first) pigified.append(" ");
       pigified.append(pigify(word));
       first = false;
   }
   return pigified.toString();
}

public static String pigify(String oneWord) {
    char[] chars = oneWord.toCharArray();
    StringBuilder consonants = new StringBuilder();
    StringBuilder newWord = new StringBuilder();
    StringBuilder punctuation = new StringBuilder();
    boolean consDone = false; // set to true when the first consonant group is done

    for (int i = 0; i < chars.length; i++) {
        // consonant
        if (vowels.indexOf(chars[i]) == -1) {
            // punctuation
            if (punct.indexOf(chars[i]) > -1) {
                punctuation.append(chars[i]);
                consDone = true;
            } else {
                if (!consDone) { // we haven't found the consonants
                    consonants.append(chars[i]);
                } else {
                    newWord.append(chars[i]);
                }
            }
        } else {
            consDone = true;
            // vowel
            newWord.append(chars[i]);
        }
    }

    if (consonants.length() == 0) {
        // vowel words are "about" -> "aboutway"
        consonants.append("w");
    } 
    consonants.append("ay");

    return newWord.append(consonants).append(punctuation).toString();
}

Answer 2

You could try to store the count of words per line in a separate data structure, and use that as a guide for when to move on to the next line when writing the file.

I purposely made this semi-vague for you, but can elaborate on request.