你如何收到你当前的php文件网址

Question

I want to make navigation easier, so lets say when i have page called

http://test.nl/admin/xxx.php?id=423

if i want to redirect to the same page with a different parameter. i can do

Header("Location: xxx.php$rest");

but is there a way to get the xxx.php dynamic? i tried $_SERVER[PHP_SELF] and it worked on localhost but not on my server. I get: http://test.nl/test.nl/admin/xxx.php?id=423

Answer 1

Try the following:

$basename = basename($_SERVER['REQUEST_URI']);

This should give you the name of the file in the URL including the extension. Of course, if you wanted to have the name of the file without the file extension then try:

$basename = str_replace(".php","",basename($_SERVER['REQUEST_URI']));

Answer 2

You should use URL rewriting. Take a look at the component Zend_Router in the Zend framework.

And for the purposes of getting the current file URL:

<?php
function curPageURL() {
     $pageURL = 'http';
     if ($_SERVER["HTTPS"] == "on") {$pageURL .= "s";}
     $pageURL .= "://";
     if ($_SERVER["SERVER_PORT"] != "80") {
          $pageURL .= $_SERVER["SERVER_NAME"].":".$_SERVER["SERVER_PORT"].$_SERVER["REQUEST_URI"];
     } else {
          $pageURL .= $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"];
     }
     return $pageURL;
}

echo curPageURL();

?>

Answer 3

Just redirect to /xxx.php?$rest . You don't need the full address if you aren't leaving the directory.

Answer 4

我不知道它在生产站点上不起作用，但在本地发生。

header("Location: {$_SERVER['REQUEST_URI']}?$rest");

Answer 5

You can use $_SERVER['SCRIPT_NAME'] variable to retrieve the current script's path ie fullpath and filename of current file

For more details about $_SERVER variable please refer the documentation mentioned in below url

http://in3.php.net/reserved.variables.server

Answer 6

You not need current url, you can link new query string:

with html link:

<a href="?foo=bar">

or php redirection:

Header("Location: ?foo=bar");

Answer 7

I like using regex for these cases. (Or rather cases where none of the other answers apply, like accessing a file relative to this one.)

$foldername = preg_replace('/(.*)(\\/admin\\/.*)/', '$2', dirname(__FILE__));

$filename = preg_replace('/(.*)(\\/admin\\/.*)/', '$2', __FILE__);

Note that \\/admin\\/ is at the start of the second capturing group. $2 gives preg replace a direct reference to the entire capturing group. Therefore admin has to be the first folder from the web root in which the capturing group resides.