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我如何获得此增量的最大值?

[英]How i can get max value of this increment?

I have increment syntax, and i want to save the last maximum value , so when i close my program and open it again , the increment will start from the last maximum value not start from 0 again .. but here my syntax always start from 0 again, so what to do ? 我有增量语法,我想保存最后一个最大值,所以当我关闭程序并再次打开它时,增量将从最后一个最大值开始,而不是从0开始..但这里我的语法总是从0开始再次,该怎么办?

   private long l = 100000;
   view.getRdbtnUmum().addActionListener(new ActionListener() {


    @Override
    public void actionPerformed(ActionEvent e) {



        if(view.getRdbtnUmum().isSelected() == true){
            view.getRdbtnPrestone().setSelected(false);
            view.getTxtJobCode().setValue("JU" + l);

        }       
        l++;
        model.setjPres(l);

    }
});

You need to persist the last value somewhere. 您需要将最后一个值保留在某个地方。 You can simply choose to write it on a simple file or you can persist it in a DB. 您可以选择将其写入简单文件中,也可以将其持久保存在数据库中。

If you can use the last maximum value, you can save the value to the file or database. 如果可以使用最后一个最大值,则可以将该值保存到文件或数据库中。

To save the value into file: 要将值保存到文件中:

 public static void serializeSumNum(int sum){         
             ObjectOutputStream oos = null;
               try{

                FileOutputStream fout = new FileOutputStream("D:\\sum\\sum.txt");
                 oos = new ObjectOutputStream(fout);   
                oos.writeObject(sum);

                System.out.println("Done");

               }catch(Exception ex){
                   ex.printStackTrace();
               }
finally {
                //Close the ObjectOutputStream
                try {
                    if (oos != null) {
                        oos .flush();
                        oos .close();
                    }
                } catch (IOException ex) {
                    ex.printStackTrace();
                }
            }
           }

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