[英]Oracle 11g: How to union an oracle table with itself?
I have a table which looks like the following: 我有一个表如下所示:
date code name score set
09/09/12 967873 Team A 24 1
09/09/12 967873 Team B 22 1
09/09/12 967873 Team A 21 2
09/09/12 967873 Team B 16 2
02/04/12 965454 Team X 21 1
02/04/12 965454 Team Y 19 1
02/04/12 965454 Team X 21 2
02/04/12 965454 Team Y 19 2
you guessed it right! 你猜对了! it's a volleyball match! 这是一场排球比赛! however, I would like my output to be in a single line. 但是,我希望我的输出只能在一行中。 For example: 例如:
date code Teams Set-1 Set-2 Set-3
09/09/12 967873 Team A VS.Team B 24-22 21-16 -
and so on....
**Notice that the game could have a third set as well
I will need some kind of self join to refine the above format to the format that is easier for Users view...Let me know if you need more details. 我需要某种自联接来将上述格式细化为用户视图更容易的格式...如果您需要更多详细信息,请告诉我。
Thanks, 谢谢,
The query could look like this: 查询可能如下所示:
with matches as (
select "DATE", code, name,
max(case when "SET" = 1 then score end) score_1,
max(case when "SET" = 2 then score end) score_2,
max(case when "SET" = 3 then score end) score_3,
row_number() over(partition by "DATE", code order by name) team_no
from games
group by "DATE", code, name
)
select a."DATE", a.code, a.name || ' vs. ' || b.name teams,
a.score_1 || '-' || b.score_1 set_1,
a.score_2 || '-' || b.score_2 set_2,
a.score_3 || '-' || b.score_3 set_3
from matches a
join matches b on a."DATE" = b."DATE" and a.code = b.code
where a.team_no = 1 and b.team_no = 2;
date and set are rather unfortunate column names. 日期和集合是相当不幸的列名。
The query works in 3 steps: 该查询分为3个步骤:
First, group the data by "date", code, "set"
to LISTAGG
the teams and the scores. 首先,按"date", code, "set"
将数据分组到LISTAGG
团队和分数。 Then pivot the results on the scores column. 然后在结果列上旋转结果。 Here's the SQL for it: 这是它的SQL:
WITH grouped AS (
SELECT
"date", code, "set",
LISTAGG(name, ' VS. ') WITHIN GROUP (ORDER BY name) AS teams,
LISTAGG(score, '-' ) WITHIN GROUP (ORDER BY name) AS score
FROM matches
GROUP BY
"date", code, "set"
)
, pivoted AS (
SELECT
"date", code, teams,
nvl("1", '-') AS set1,
nvl("2", '-') AS set2,
nvl("3", '-') AS set3
FROM grouped
PIVOT (
MAX(score) FOR "set" IN (1, 2, 3)
) p
)
SELECT * FROM pivoted
;
Please have a look at this query at SQL Fiddle too. 请在SQL Fiddle上查看此查询。
I'd do sg like this, if the name of the table is let's say VOLLEYBALL: 我会这样做,如果表的名字让我们说VOLLEYBALL:
SELECT temp.date, temp.code,
temp.team1 || ' vs. ' || temp.team2 AS teams,
(SELECT v.score FROM volleyball v WHERE v.code = temp.code AND v.name = team1 AND v.set = 1) || '-' ||
(SELECT v.score FROM volleyball v WHERE v.code = temp.code AND v.name = team2 AND v.set = 1) AS set1,
(SELECT v.score FROM volleyball v WHERE v.code = temp.code AND v.name = team1 AND v.set = 2) || '-' ||
(SELECT v.score FROM volleyball v WHERE v.code = temp.code AND v.name = team2 AND v.set = 2) AS set2,
nvl((SELECT v.score FROM volleyball v WHERE v.code = temp.code AND v.name = team1 AND v.set = 3) || '-' ||
(SELECT v.score FROM volleyball v WHERE v.code = temp.code AND v.name = team2 AND v.set = 3)
, '-') AS set3 -- optional, if no results, then it will be a '-'
FROM
(SELECT v.date, v.code,
min(v.name) AS team1, max(v.name) AS team2
FROM volleyball v
GROUP BY v.date, v.code) temp;
This will result a one row summary. 这将产生一行摘要。
To return the required results without needing a join, try: 要在不需要连接的情况下返回所需结果,请尝试:
select "date",
code,
min_name || ' VS. ' || max_name teams,
sum(case when "set" = 1 and name = min_name then score end) || '-' ||
sum(case when "set" = 1 and name = max_name then score end) "Set-1",
sum(case when "set" = 2 and name = min_name then score end) || '-' ||
sum(case when "set" = 2 and name = max_name then score end) "Set-2",
sum(case when "set" = 3 and name = min_name then score end) || '-' ||
sum(case when "set" = 3 and name = max_name then score end) "Set-3"
from (select g.*,
min(name) over (partition by "date", code) min_name,
max(name) over (partition by "date", code) max_name
from games)
group by "date", code
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