如何在linux中获取倒数第二个文件夹的名称

Question

I have to write a shell script in linux in which i have to pull the name of the second last folder of the given path. For example:-

/var/www/html/folder1/folder2/folder3

How can i get only the name of second last folder "folder2" using a command?

Note: My shell script is placed at root (/var/www/html)

Answer 1

Using awk:

awk -F/ '{print $(NF-1)}' <<< "/var/www/html/folder1/folder2/folder3"

Alternatively, call basename on the dirname .

basename "$(dirname /var/www/html/folder1/folder2/folder3)"

Answer 2

you can use sed to get it:

export some_path="/var/www/html/folder1/folder2/folder3"
export folder_place2=`echo $some_path  | sed -e "s/.*\/\([^/]*\)\/[^/]*/\1/"`
echo $folder_place2