[英]Column 'u_id' in where clause is ambiguous
SELECT `attendence`.`u_id` ,
DATE_FORMAT(date,'%d-%m-%Y') as `date`,
`attendence`.`checkin`,
`attendence`.`checkout`,
`users`.`firstname`,
`users` .`lastname`
FROM `attendence`
INNER JOIN `users` ON `attendence`.`u_id` = `users`.`u_id`
WHERE DATE_FORMAT( DATE, '%Y-%m' ) = '$combined' AND `u_id`='$u_id';
please help guys 请帮助大家
when i removed AND u_id
='#u_id it works but returns all employee details' 当我删除AND u_id
='#u_id时,它可以工作,但返回所有员工详细信息'
you need to specify what table should the column u_id
came from since both tables has this column. 您需要指定u_id
列u_id
来自哪个表,因为两个表都具有该列。
AND `attendence`.`u_id`='$u_id';
OR 要么
AND `users`.`u_id`='$u_id';
choose one that satifies your needs. 选择一种满足您需求的产品。 Anyway, either of the two functions the same since they are the linking columns of both tables. 无论如何,这两个函数之一是相同的,因为它们是两个表的链接列。
replace 更换
`u_id`='$u_id';
by 通过
`users`.`u_id`='$u_id';
If you have u_id
in multiple tables that you are using in your query then you need to specify which u_id
you want to use. 如果在查询中使用的多个表中都有u_id
,则需要指定要使用的u_id
。
use this in your where clause: 在where子句中使用它:
`attendence`.`u_id` = '$u_id';
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